Question

我有一个关于关联数组的问题我由于缺乏编程知识而无法自行解决。

我有一个从数字“1”到“12”的foreach循环。对于每个号码，我得到一个从另一个服务器提取数据的链接。

这个数据具有json数组的形式，所以我为每个键值类型创建单个数组，我从json数据中提取（例如雇主名称;雇主ID;雇主薪水; ......）和CURL。

我需要将所有这些数据插入到数据库中，因此我创建了一个包含所有这些数据的数组，而不是将所有这些数据插入到表中。但是......如果我必须从第一个foreach创建最终的单个数组我没有问题，但是我无法继续从第二个foreach到最后一个已经存在的最终数组...... 我需要像这样工作的原因可能是从Json数组中提取的数据包含相同的ex。雇主两次，所以我想创建最终阵列而不重复。

以下是代码：

createUrl();

function createUrl() {

$serverName = 'test';
$iscountryID = 'test';
$countryCurrency = 'test';
$countryName = 'test';

// TAX url (here I get tax data)*******************************
$urlTaxcountry =  strtolower("https://www.test.org/".$serverName."/tax/".$iscountryID.".json");

// CURRENCY EXCHANGE url **********************
$urlChangeCurrencySell = strtolower("https://www.test.org/".$serverName."/exchange/gold-".$countryCurrency.".json"); // to change currency value in gold    

$Skill = array(1,2,3,4,5,6,7,8,9,10,11,12);

foreach ($Skill as $workSkill) {
   // JOBS url *******************************
   $urlJobcountry = strtolower("https://www.test.org/".$serverName."/job/".$iscountryID."-".$workSkill.".json"); 

  getJsonData($serverName,$iscountryID,$workSkill,$urlJobcountry,$urlChangeCurrencySell,$urlTaxcountry,$countryCurrency,$countryName);
}};

 function getJsonData($serverName,$iscountryID,$workSkill,$urlJobcountry,$urlChangeCurrencySell,$urlTaxcountry,$countryCurrency,$countryName)
    {


    $arrEmpName = array();      
    $arrEmpID = array();
    $arrProduct = array();
    $arrQuality = array();
    $arrSkill = array();
    $arrSalary = array();
    $arrKeys = array();
    $i = 0;

    if ($iscountryID != NULL) {
    // FOR JOBS         
    $chJob = curl_init($urlJobcountry);
    curl_setopt($chJob, CURLOPT_RETURNTRANSFER, true);
    $resultJob = curl_exec($chJob);
    $outLoopJob = json_decode($resultJob, true);

    $marketCountryID = $outLoopJob['country']['id'];
    $marketCountryName = $outLoopJob['country']['name'];

    $f = 0;

    $dataJob = $outLoopJob['offers'];
    foreach($dataJob as $job) 
            { 
                $empCompanyID = ($job['company']['id']);
                $empCompanyName = ($job['company']['name']);
                $empProduct = ($job['product']);
                $empQuality = ($job['quality']);
                $empSkill = ($job['skill']);
                $empSalary = ($job['salary']);  

                // CHECK
                echo "<br>empCompanyID: ".$empCompanyID;
                echo "<br>empCompanyName: ".$empCompanyName;
                echo "<br>empProduct: ".$empProduct;
                echo "<br>empQuality: ".$empProduct;
                echo "<br>empSkill: ".$empSkill;
                echo "<br>empSalary: ".$empSalary;

                $arrEmpName[] = $empCompanyName;        
                $arrEmpID[] = $empCompanyID;
                $arrProduct[] = $empProduct;
                $arrQuality[] = $empQuality;
                $arrSkill[] = $empSkill;
                $arrSalary[] = $empSalary;
                $arrKeys[] = $i++;
                $r++;
            }}

        //$result = array_merge($arrKeys, $arrEmpName, $arrEmpID, $arrProduct, $arrQuality, $arrSkill, $arrSalary); 

        $allJobs = array();

        foreach ($arrKeys as $id => $key) {
            if (empty($allJobs)) {
                $allJobs[$key] = array(
                'EmployerName' => $arrEmpName[$id],
                'EmployerID' => $arrEmpID[$id],
                'Product' => $arrProduct[$id],
                'Quality' => $arrQuality[$id],
                'Skill' => $arrSkill[$id],
                'Salary' => $arrSalary[$id],);
            } elseif ((!in_array($empCompanyID, $allJobs)) && (!in_array($empCompanyName, $allJobs)) && (!in_array($empProduct, $allJobs)) && (!in_array($empQuality, $allJobs)) && (!in_array($empSkill, $allJobs)) && (!in_array($empSalary, $allJobs))) {

比我尝试过：

                $allJobs[$key] = array(
                'EmployerName' => $arrEmpName[$id],
                'EmployerID' => $arrEmpID[$id],
                'Product' => $arrProduct[$id],
                'Quality' => $arrQuality[$id],
                'Skill' => $arrSkill[$id],
                'Salary' => $arrSalary[$id]);

而不是

                array_push($allJobs, ("'EmployerName' => ".$arrEmpName[$id]), ("'EmployerID' => ".$arrEmpID[$id]), "'Product' => ".$arrProduct[$id], "'Quality' => ".$arrQuality[$id], "'Skill' => ".$arrSkill[$id], "'Salary' => ".$arrSalary[$id]);
                $f++;
            }};

两者都不起作用...... 而代码的结尾如下：

        // se no entry, write no record
        if  ($empCompanyID == NULL)
            {
                $marketCountryName = $countryName;  // NBBBBBBBBBB
                $empCompanyName = 'No Record';
                $empProduct = 'No Record';
                $empQuality = 'No Record';
                $empSkill = 'No Record';
                $empSalary = 'No Record';
            }; 
        }


        echo "<br>this is allJobs:<br>";
        print_r($allJobs);
        echo "<br>";
        print_r($result);   
   };

感谢您的时间和帮助。

更新

我们走了：这是我从Json文件中获取的数据

{"country":
{"id":24
,"name":"Argentina"
}
,"offers":[
    {"company":
        {"id":12767
            ,"name":"Armas Q5 Argentina "
        }
        ,"product":"Weapon"
        ,"quality":5
        ,"skill":8
        ,"salary":25
    }
    ,{"company":
        {"id":12767
            ,"name":"Armas Q5 Argentina "
        }
        ,"product":"Weapon"
        ,"quality":5
        ,"skill":1
        ,"salary":25
    }
    ,{"company":
        {"id":16587
             ,"name":"International bank of Railman"
        }
        ,"product":"Iron"
        ,"quality":1
        ,"skill":1
        ,"salary":1
    }
]
,"load":1.4469039440155
}

此特定数据是从对应于文件阿根廷的文件中获得的，具有工作技能8。您必须检查所有技能级别以获得从1到12的完整作业市场数据。每个页面仅返回15个结果，并且可能发生“公司xx”也出现在Skill Work ex的页面中。 “3”和“2”。

我要做的是从所有工作技能页面（从1到12）中提取数据并创建一个不重复的数组，如：

  [0] => ['EmployerName'] => test ['EmployerID'] => 18768 ['Product'] => test ['Quality'] => 5 ['Skill'] => 12 ['Salary'] => 35.5 ) 
  [1] => ['EmployerName'] => test ['EmployerID'] => 10844 ['Product'] => test ['Quality'] => 5 ['Skill'] => 12 ['Salary'] => 35.01)
  [2] => ['EmployerName'] => ...

更新2

但如果我只使用：

  } elseif ((!in_array($empCompanyID, $allJobs)) &&   (!in_array($empCompanyName, $allJobs)) && (!in_array($empProduct, $allJobs)) && (!in_array($empQuality, $allJobs)) && (!in_array($empSkill, $allJobs)) && (!in_array($empSalary, $allJobs))) {
                $allJobs[$key] = array(
                'EmployerName' => $arrEmpName[$id],
                'EmployerID' => $arrEmpID[$id],
                'Product' => $arrProduct[$id],
                'Quality' => $arrQuality[$id],
                'Skill' => $arrSkill[$id],
                'Salary' => $arrSalary[$id]);
                $f++;
            }};

我得到了这个奇怪的结果......：

抱歉，但不能理解为什么......

更新3

以下是我的示例中的“allJobs数组”的2个示例：第一个是从SKILL PAGE 2获得的（循环的第二个值），第二个来自SKILL PAGE 3

这是allJobs（工作技能2）：

 Array ( [0] => Array ( [EmployerName] => Air Veneto Q1 -1 [EmployerID] => 3481 [Product] => Iron [Quality] => 2 [Skill] => 2 [Salary] => 12.01 ) [1] => Array ( [EmployerName] => Israel Weap Q3 [EmployerID] => 2533 [Product] => Weapon [Quality] => 3 [Skill] => 2 [Salary] => 11 ) [2] => Array ( [EmployerName] => Israel Weap Q3 [EmployerID] => 2533 [Product] => Weapon [Quality] => 3 [Skill] => 1 [Salary] => 10.61 ) [3] => Array ( [EmployerName] => Traforis [EmployerID] => 15848 [Product] => Oil [Quality] => 4 [Skill] => 2 [Salary] => 9.05 ) [4] => Array ( [EmployerName] => 1weapQ5 [EmployerID] => 10431 [Product] => Weapon [Quality] => 5 [Skill] => 1 [Salary] => 7.2 ) [5] => Array ( [EmployerName] => WAR 1111 [EmployerID] => 17753 [Product] => Iron [Quality] => 5 [Skill] => 2 [Salary] => 7.1 ) [6] => Array ( [EmployerName] => Silent murder [EmployerID] => 16005 [Product] => Weapon [Quality] => 1 [Skill] => 1 [Salary] => 6.5 ) [7] => Array ( [EmployerName] => NK Iron [EmployerID] => 16745 [Product] => Iron [Quality] => 3 [Skill] => 2 [Salary] => 6.5 ) [8] => Array ( [EmployerName] => NK Iron [EmployerID] => 16745 [Product] => Iron [Quality] => 3 [Skill] => 1 [Salary] => 5 ) [9] => Array ( [EmployerName] => Air Veneto Q1 -1 [EmployerID] => 3481 [Product] => Iron [Quality] => 2 [Skill] => 1 [Salary] => 5 ) [10] => Array ( [EmployerName] => Helvetia Eisen [EmployerID] => 10673 [Product] => Iron [Quality] => 4 [Skill] => 1 [Salary] => 3 ) [11] => Array ( [EmployerName] => Olimpiaki A.E. [EmployerID] => 7156 [Product] => Ticket [Quality] => 1 [Skill] => 1 [Salary] => 1.01 ) [12] => Array ( [EmployerName] => Africa Oil Corp. [EmployerID] => 18180 [Product] => Oil [Quality] => 2 [Skill] => 1 [Salary] => 1 ) [13] => Array ( [EmployerName] => Hardika Olaj #1 [EmployerID] => 7861 [Product] => Oil [Quality] => 3 [Skill] => 1 [Salary] => 1 ) [14] => Array ( [EmployerName] => GD & Co. [EmployerID] => 18770 [Product] => Weapon [Quality] => 1 [Skill] => 1 [Salary] => 1 ) )

这是allJobs（工作技能3）：

如你所见，

  Array ( [EmployerName] => Air Veneto Q1 -1 [EmployerID] => 3481 [Product] => Iron [Quality] => 2 [Skill] => 2 [Salary] => 12.01

重复两次，两个条目完全相同。

更新4（解决方案）

好吧，我无法用关联数组来解决我的问题，所以（这可能对其他人有用，我稍后在代码中进行检查，就在将数据插入数据库之前。

因此，当我发现所有VARS已作为存储在DB中的值存在时，代码跳转到下一部分，避免再次添加相同的值。

这是代码：

 function addJobs($iscountryID, $countryName, $countryCurrency,  $empCompanyID, $empCompanyName, $empProduct, $empQuality, $empSkill, $empSalary, $Changerate, $goldJob, $taxIncome, $netgoldJob, $serverName, $linktopageJob, $linktoEmployer, $dayTimeJob, $timeJob, $Currencysell, $marketCountryID, $marketCountryName)

{

 // db connection
 require "db-connection/db-connection2.php";

 $sqlfind = "SELECT 
 ID 
 FROM cJM".$serverName." 
 WHERE (
 iscountryID = ? 
 AND countryName = ? AND countryCurrency = ? 
 AND empCompanyID = ? AND empCompanyName = ? 
 AND empProduct = ? AND empQuality = ? 
 AND empSkill = ? AND empSalary = ? 
 AND goldExchange = ? AND salaryinGold = ? 
 AND jobTax = ? AND netSalary = ? AND Server = ?
 AND time_of_record = ? AND DateSave = CURDATE()
 )";

 echo "<b><br><br>*********************POST***********************</b>";
 echo "<br>empCompanyID: ".$empCompanyID;
 echo "<br>empCompanyName: ".$empCompanyName;
 echo "<br>empProduct: ".$empProduct;
 echo "<br>empQuality: ".$empProduct;
 echo "<br>empSkill: ".$empSkill;
 echo "<br>empSalary: ".$empSalary;                 
 echo "<br>is country id: ".$iscountryID;
 echo "<br>country name: ".$countryName;
 echo "<br>country currency: ".$countryCurrency;
 echo "<br>gold exchange rate: ".$Changerate;
 echo "<br>job tax: ".$taxIncome;
 echo "<br>server name: ".$serverName;
 echo "<br>link to market: ".$linktopageJob;
 echo "<br>market country ID: ".$marketCountryID;
 echo "<br>market country Name: ".$countryName;
 echo "<br>time Job: ".$timeJob;
 echo "<br>day time Job: ".$dayTimeJob;
 echo "<br>gold Job: ".$goldJob;
 echo "<br>net gold job: ".$netgoldJob;
 echo "<br>link to employer: ".$linktoEmployer;
 echo "<br>currency Sell: ".$Currencysell;
 echo "<br>**********************END POST**********************<br><br>";
 echo_flush();

 echo "check $serverName";
 if ($stmt = $conn->prepare($sqlfind)) {
      $stmt->bind_param('sississiiiiiiis', $iscountryID, $countryName, $countryCurrency, $empCompanyID, $empCompanyName, $empProduct, $empQuality, $empSkill, $empSalary, $Changerate, $goldJob, $taxIncome, $netgoldJob, $serverName, $dayTimeJob);

     /* execute query */
     $stmt->execute();

     /* Store the result (to get properties) */
     $stmt->store_result();

     /* Get the number of rows */
     $num_of_rows = $stmt->num_rows;

     echo "<br>there are $num_of_rows results corresponding to requested search<br>";

     if ($num_of_rows == 0) {
        echo "THERE AREN'T RESULTS!";

        // SQLI INSERT
        $sqlJobIns = "INSERT INTO cJM".$serverName." (iscountryID, countryName, countryCurrency, empCompanyID, empCompanyName, empProduct, empQuality, empSkill, empSalary, goldExchange, salaryinGold, jobTax, netSalary, Server, link_to_page, link_to_employer, time_of_record, DateSave) VALUES (?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, ?, CURDATE())";  // ADD NEW RECORDS

        if($stmt = $conn->prepare($sqlJobIns)) {
            $stmt->bind_param('ississiiiiiiiisss', $iscountryID, $countryName, $countryCurrency, $empCompanyID, $empCompanyName, $empProduct, $empQuality, $empSkill, $empSalary, $Changerate, $goldJob, $taxIncome, $netgoldJob, $serverName, $linktopageJob, $linktoEmployer, $dayTimeJob);

            /* execute query */
            $stmt->execute();
            $stmt->store_result();

            echo "<br>check $serverName";

            //var_dump($stmt);
            $num_of_rows_INS = $stmt->num_rows; 
            echo "<br>Check if data have been inserted: ";

            if ($stmt) {
                // RETURN AMOUNT OF DATA INSERT
                printf("added %d\n records to the DB...<br>", $stmt->affected_rows);        
            } else {
                echo "<br>there was a problem with data insert...<br>";
        }}
     } else echo ("<br>WE HAVE RESOULTS!");

     /* Bind the result to variables */
     $stmt->bind_result($idDB);

     while ($stmt->fetch()) {
        echo "<br>id from DATABASE is: ".$idDB;
     };
    /* free results */
    $stmt->free_result();
    /* close statement */
    $stmt->close();
 }};

感谢您的时间。希望这段代码可以帮助其他人。

阿尔贝托

Answer 1

如果产品，技能和薪水都与雇主提供的工作相关，那么您可以填充您的数组:(请注意它使用您的变量名称的简写）

在循环遍历json数组时使用它。

if (isset ($employers ['employer id']))
    $employers ['employer id'] = array ( 'name' => 'employer name', 'jobs' => array ('skill' => 'the skill', 'quality' => 'the quality', 'product' => 'the product', 'salary' => 'the salary'));
else
    $employers ['employer id']['jobs'][] = array('skill' => 'the skill', 'quality' => 'the quality', 'product' => 'the product', 'salary' => 'the salary'));

使用嵌套的foreach来取回数据。像：

$allJobs = array ();
foreach ($employers as $employer) {
    for ($employer ['jobs'] as $job) {
        $allJobs[] = array(
            'EmployerName' => $employer['name'],
            'EmployerID' => $employer['id'],
            'Product' => $job['product'],
            'Quality' => $job['quality'],
            'Skill' => $job['skill'],
            'Salary' => $job['salary']);
    } 
}

PHP如何将键和值添加到关联数组

1 个答案: