Question

我有这些表格：

部

DEPARTMENT_ID DEPARTMENT_NAME      ADDRESS            
------------- -------------------- --------------------
       10 ACCOUNTING           NEW YORK            
       20 RESEARCH             DALLAS              
       30 SALES                CHICAGO             
       40 IT                   DALLAS              
       50 EXECUTIVE            NEW YORK            
       60 MARKETING            CHICAGO

雇员

Employee_ID  employee_name  job                     manager_ID  hire_date  salary  commission  department_ID
------------------------------------------------------------------------------------------------------------
7839        KING            PRESIDENT                           20-NOV-01   5000                50
7596        JOST            VICE PRESIDENT          7839        04-MAY-01   4500                50
7603        CLARK           VICE PRESIDENT          7839        12-JUN-01   4000                50
7566        JONES           PUBLIC ACCOUNTANT       7596        05-APR-01   3000                10
7886        STEEL           PUBLIC ACCOUNTANT       7566        08-MAR-03   2500                10
7610        WILSON          ANALYST                 7596        03-DEC-01   3000                20
7999        WOLFE           ANALYST                 7610        15-FEB-02   2500                20
7944        LEE             ANALYST                 7610        04-SEP-06   2400                20
7900        FISHER          SALESMAN                7603        06-DEC-01   3000    500         30
7921        JACKSON         SALESMAN                7900        25-FEB-05   2500    400         30
7952        LANCASTER       SALESMAN                7900        06-DEC-06   2000    150         30
7910        SMITH           DATABASE ADMINISTRATOR  7596        20-DEC-01   2900                40
7788        SCOTT           PROGRAMMER              7910        15-JAN-03   2500                40
7876        ADAMS           PROGRAMMER              7910        15-JAN-03   2000                40
7934        MILLER          PROGRAMMER              7876        25-JAN-02   1000                40
8000        BREWSTER        TBA                                 22-AUG-13   2500

我需要显示名称和地址，但达拉斯除外，拥有最多的员工数。

我写了这个：

SELECT department_name, address
FROM department
WHERE department_id IN
                 (SELECT   MAX(department_id)
                  FROM     department
                  WHERE    UPPER(address) != 'DALLAS')
ORDER BY department_name;

但我只得到一行

DEPARTMENT_NAME      ADDRESS            
-------------------- --------------------
MARKETING            CHICAGO

我做错了什么？

Answer 1

不确定我理解你的问题，但我想你想要这个：

algebraixlib

返回：

with emp_count as (
  select d.department_name,
         d.address,
         count(*) as num_emps, 
         max(count(*)) over () as max_count
  from department d 
    join employee e on d.department_id = e.department_id
  where address <> 'DALLAS'
  group by d.department_name, d.address
)
select * 
from emp_count
where num_emps = max_count;

SQLFiddle示例：http://sqlfiddle.com/#!4/05db83/1

Answer 2

根据您的示例数据，该城市似乎记录在address表的department列中，并且多个部门可以拥有相同的城市。

考虑到这一点，以及你想要“排除达拉斯”的事实，正如你所说，我认为你想要过滤掉相关address列是'达拉斯'的所有部门。

然而，我不知道是否......

如果他们恰好与大多数员工的其他部门联系在一起，你想要在达拉斯排除部门，或者
如果您想在确定任何部门的员工人数最多时考虑将达拉斯的部门排除在外。

如果（1）为真：

select *
  from department_tbl
 where department_id in (select department_id
                           from employee_tbl
                          group by department_id
                         having count(*) = (select max(num_emps)
                                             from (select department_id,
                                                          count(*) as num_emps
                                                     from employee_tbl
                                                    group by department_id)))
   and address <> 'DALLAS';

如果（2）为真：

select *
  from department_tbl
 where department_id in (select department_id
                           from employee_tbl
                          group by department_id
                         having count(*) = (select max(num_emps)
                                             from (select department_id,
                                                          count(*) as num_emps
                                                     from employee_tbl
                                                    where address <> 'DALLAS'
                                                    group by department_id)));

Answer 3

试试这个。

SELECT d.department_name, 
       d.address 
FROM   department d 
       JOIN employee e 
         ON ( d.department_id = e.department_id ) 
WHERE  d.address <> 'DALLAS' 
GROUP  BY d.department_name, 
          d.address 
HAVING Count(*) = (SELECT Max(cnt) 
                   FROM   (SELECT Count(*) CNT 
                           FROM   employee e 
                           WHERE  NOT EXISTS (SELECT 'x' 
                                              FROM   department d 
                                              WHERE  d.department_id = 
                                                     e.department_id 
                                                     AND d.address = 'DALLAS') 
                           GROUP  BY department_id))

Answer 4

select e.department_id, d.department_name, count(e.department_id)
from employee e, department d
where e.department_id = d.department_id
group by e.department_id, d.department_name 
having count(e.department_id)=(select max(count(department_id)) 
                               from employee 
                               group by department_id);

希望有所帮助

SQL - 选择具有最大员工数的所有部门的名称和地址

4 个答案: