Question

我使用key：reportData和值数组

以这种方式获得JSON数据

 {"reportData":[
    ["1185","R","4t","G","06","L","GT","04309","2546","2015","CF FE","01H1","20","23840","FF20"],
    ["1186","R","5t","R","01","L","TP","00110","1854","2016","FE LL","06W3","01","19065","FB01"],
    ["1187","R","6t","H","06","L","TP","04333","1864","2015","CF FE SL","0209","FD22","19845",null],
    ["1188","R","7t","H","06","L","PR","04041","6951","2015","CC CT FE GN PC","0070","00","36590","LB00"],
    ["1189","R","8t","H","06","L","WS","04290","4450","2014","CF   EN   FE   PC   TP","0070","EA30","28320.00",null],
    ["1190","R","9t","H","06","L","LA","04915","4430","2015","CF DK FE RR TC","0040","10","23680","FB10"],
    ["1191","R","10t","H","06","L","LF","04335","2532","2015","CF FE GE","0040","FC10","22970",null],
    ["1192","R","11t","H","06","L","SA","04772","8345","2015","BZ C8 FE","01D6","13","33390","LC13"]]}

我想比较和交换每个数组元素中的数据：特别是第12和第14个索引。

ex: in "reportData":[
    ["1185","R","4t","G","06","L","GT","04309","2546","2015","CF FE","01H1","20","23840","FF20"]]

即，我想比较和交换＆＃39; 20＆＃39;与＆＃39; FF20＆＃39;使用这个逻辑。

If 14th index value != null then assign,

   12th index=14th index value.

else if 14th index value ==null,

then leave 12th index=12th index value as it is.

对于＆＃34; reportData＆＃34;中的所有数组列表，必须重复此操作。键。

所以，我的最终JSON就是这样，

    "reportData":[
["1185","R","4t","G","06","L","GT","04309","2546","2015","CF FE","01H1","FF20","23840","FF20"],//interchange 12th with 14th as 14th !=null
["1186","R","5t","R","01","L","TP","00110","1854","2016","FE LL","06W3","FB01","19065","FB01"],//interchange 12th with 14th as 14th !=null
["1187","R","6t","H","06","L","TP","04333","1864","2015","CF FE SL","0209","FD22","19845",null],//leave 12th as IT IS as 14th ==null
["1188","R","7t","H","06","L","PR","04041","6951","2015","CC CT FE GN PC","0070","00","36590","LB00"],//interchange 12th with 14th as 14th !=null
["1189","R","8t","H","06","L","WS","04290","4450","2014","CF   EN   FE   PC   TP","0070","EA30","28320.00",null],//leave 12th as IT IS as 14th ==null
["1190","R","9t","H","06","L","LA","04915","4430","2015","CF DK FE RR TC","0040","10","23680","FB10"],//interchange 12th with 14th as 14th !=null
["1191","R","10t","H","06","L","LF","04335","2532","2015","CF FE GE","0040","FC10","22970",null],//leave 12th as IT IS as 14th ==null
["1192","R","11t","H","06","L","SA","04772","8345","2015","BZ C8 FE","01D6","13","33390","LC13"]]//interchange 12th with 14th as 14th !=null

我试过这种方式，但它正在互换，

function swapJsonKeyValues(input) {
        var one=['FCOL,ICOL']; output = {};
        for (one in input) {
            if (input.hasOwnProperty(one)) {
                output[input[one]] = one;
            }
        }
        return output;
    }

有谁可以帮我解决这个问题？

Answer 1

假设data = json对象，那么

data.reportData.forEach(function(row){
    if(row[14] != null)
        row[12] = row[14];
});

Answer 2

不确定示例函数中包含FCOL和ICOL的数组是什么，但这是解决此问题的一种方法。

我调用了函数copyElement，因为swapJsonKeyValues不起作用。 1）假设你已经解析了数据，它现在是一个JS对象，而不是JSON 2）你没有交换键/值对，你只是根据条件复制一个元素。

所有函数都检查每个数组的长度是否至少为14个元素，如果是，则检查第14个元素是否不是null。如果是将值复制到元素12. map只是在reportData中的每个数组上运行回调后返回一个新数组。

function copyElement(obj) {
  return obj.reportData.map(function (el) {
     if (el.length >= 14 && el[14] !== null) el[12] = el[14];
     return el;
  });
}

copyElement(obj);

DEMO

Answer 3

你可以试试这个：

var jsonData =  {"reportData":[
    ["1185","R","4t","G","06","L","GT","04309","2546","2015","CF FE","01H1","20","23840","FF20"],
    ["1186","R","5t","R","01","L","TP","00110","1854","2016","FE LL","06W3","01","19065","FB01"],
    ["1187","R","6t","H","06","L","TP","04333","1864","2015","CF FE SL","0209","FD22","19845",null],
    ["1188","R","7t","H","06","L","PR","04041","6951","2015","CC CT FE GN PC","0070","00","36590","LB00"],
    ["1189","R","8t","H","06","L","WS","04290","4450","2014","CF   EN   FE   PC   TP","0070","EA30","28320.00",null],
    ["1190","R","9t","H","06","L","LA","04915","4430","2015","CF DK FE RR TC","0040","10","23680","FB10"],
    ["1191","R","10t","H","06","L","LF","04335","2532","2015","CF FE GE","0040","FC10","22970",null],
    ["1192","R","11t","H","06","L","SA","04772","8345","2015","BZ C8 FE","01D6","13","33390","LC13"]]}

jsonData.reportData.map(function (row) {return row[12] = (row[14]) ? row[14] : row[12];})
console.log(jsonData);

地图回调函数将检查这些条件并返回所需的数据。

JSON - 如何通过比较特定键彼此来交换值？

3 个答案: