if（isset（$ _ POST [＆＃39; Name＆＃39;]）＆amp;＆amp; isset（$ _ POST [＆＃39; Number＆＃39;]））总是在PHP中返回false

Question

// xamarin.android c# code 
void mButtonCreateContact_Click(object sender, EventArgs e)
{
    WebClient client = new WebClient();
    Uri uri = new Uri("http://www.mydomainname.com/abcd.php");
    NameValueCollection parameters = new NameValueCollection();
    parameters.Add("Name", txtName.Text);
    parameters.Add("Number", txtNumber.Text);`
    client.UploadValuesCompleted += client_UploadValuesCompleted;
    client.UploadValuesAsync(uri, parameters);          
}

这里我传递了两个参数来获取用户的输入。但是在PHP代码中它始终在isset['Name']函数中返回false并进入else语句

if (isset($_POST['Name']) && isset($_POST['Number']))
{
    $mName = $_POST['Name'];
    $mNumber = $_POST['Number'];
    echo 'true';
}
else
{
    echo 'false';
}

Answer 1

您需要在WebClient中设置请求参数POST。

Answer 2

您目前正在发送带有值的GET，如果您想使用POST，请将其称为：

void mButtonCreateContact_Click(object sender, EventArgs e)
    {
        WebClient client = new WebClient();
        Uri uri = new Uri("http://www.mydomainname.com/abcd.php");
        NameValueCollection parameters = new NameValueCollection();
        parameters.Add("Name", txtName.Text);
        parameters.Add("Number", txtNumber.Text);
        client.UploadValuesCompleted += client_UploadValuesCompleted;
        client.Headers[HttpRequestHeader.ContentType] = "application/x-www-form-urlencoded";
        client.UploadValuesAsync(uri, "POST", parameters);          
    }

Answer 3

使用以POST

查看

client.UploadValuesAsync(uri, "POST", parameters);

Answer 4

最佳方式是用户$_REQUEST。无论你使用帖子还是获得。