我有一个程序,我的代码使用goto语句,我希望以一种很好的方式摆脱它,但我似乎无法找到解决方案。如果goto是最好的方式,请告诉我。以下是代码摘要:
//Counts how many times every word appears in a file
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#define NUMWORDS 1000
#define WORDLEN 50
typedef struct
{
char word[WORDLEN + 1];
int num;
} Appearance;
int main(int argc, char *argv[]) {
FILE *readfile;
Appearance *appearlist[NUMWORDS] = {NULL};
char word[WORDLEN + 1];
int i;
//Get a valid filename and open the file, store pointer into readfile
...
char c;
while (c != EOF) {
skip: //Annoying label
//Get a word from readfile, store into word
...
if (word[0] != '\0') {
for (i = 0; i < NUMWORDS && appearlist[i]; i++) {
if (strcmp(appearlist[i] -> word, word) == 0) {
appearlist[i] -> num++;
goto skip; //Annoying goto
}
}
appearlist[i] = (Appearance *) malloc(sizeof(Appearance));
appearlist[i] -> num = 1;
strcpy(appearlist[i] -> word, word);
}
}
//Display results, free memory
...
return 0;
}
问题是,我想跳过我想跳过的循环之外的代码。我想不创建另一个仅为此设计的变量。如果您需要完整代码,请单击&#34;显示代码段。&#34;
//Counts how many times every word appears in a file
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#define NUMWORDS 1000
#define WORDLEN 50
#define FILENAMELEN 50
typedef struct
{
char word[WORDLEN + 1];
int num;
} Appearance;
int main(int argc, char *argv[])
{
char filename[FILENAMELEN];
FILE *readfile;
Appearance *appearlist[NUMWORDS] = {NULL};
char word[WORDLEN + 1];
size_t ln;
int i;
if (argc == 2)
strncpy(filename, argv[1], sizeof(filename));
else {
printf("Enter a filename to count appearances from, or just press enter to quit: ");
fgets(filename, FILENAMELEN, stdin);
ln = strlen(filename) - 1;
if (filename[ln] == '\n')
filename[ln] = '\0';
}
while((readfile = fopen(filename, "r")) == NULL) {
if (filename[0] == '\0')
return 0;
printf("Invalid file! Please enter another filename, or just press enter to quit: ");
fgets(filename, FILENAMELEN, stdin);
ln = strlen(filename) - 1;
if (filename[ln] == '\n') filename[ln] = '\0';
}
char c;
while (c != EOF) {
skip:
for (i = 0; (c = getc(readfile)) != EOF && (isalnum(c) || c == '\''); i++) {
if (i >= WORDLEN) {
word[i] = '\0';
printf("\nWarning: word too long (over %d characters), trimming to: %s\n", WORDLEN, word);
while ((c = getc(readfile)) != EOF && (isalnum(c) || c == '\'')) ;
} else {
word[i] = tolower(c);
}
}
word[i] = '\0';
if (word[0] != '\0') {
for (i = 0; i < NUMWORDS && appearlist[i]; i++) {
if (strcmp(appearlist[i] -> word, word) == 0) {
appearlist[i] -> num++;
goto skip;
}
}
appearlist[i] = (Appearance *) malloc(sizeof(Appearance));
appearlist[i] -> num = 1;
strcpy(appearlist[i] -> word, word);
}
}
for (i = 0; i < NUMWORDS && appearlist[i]; i++) {
printf("Word: %s, Appearances: %d\n", appearlist[i] -> word, appearlist[i] -> num);
free(appearlist[i]);
}
return 0;
}
&#13;
答案 0 :(得分:1)
在这种情况下使用goto
通常被认为是可以接受的。
替代方法是设置一个变量,以便在continue
内部循环之后可以在外循环中break
,或者将要逃离的整个段转换为单独的函数,并从中返回,而不是使用goto
。
我忽略了与问题无关的代码可能存在的任何其他问题!
答案 1 :(得分:1)
将以“if”语句开头的所有内容放入单独的方法中(让我们将其称为“进程”并将goto
替换为return
。然后while循环变为:
while (c != EOF) {
//Get a word from readfile, store into word
...
process(...);
}
答案 2 :(得分:0)
有时候使用goto
提示代码应该使用辅助函数
static bool findword(Appearance *appearlist, size_t size, const char *word) {
for (size_t i = 0; i < size && appearlist[i]; i++) {
if (strcmp(appearlist[i]->word, word) == 0) {
appearlist[i]->num++;
return true;
}
}
return false;
}
while (c != EOF) {
//Get a word from readfile, store into word
...
if (word[0] != '\0') {
if (findword(appearlist, NUMWORDS, word)) {
continue;
}
appearlist[i] = (Appearance *) malloc(sizeof(Appearance));
appearlist[i] -> num = 1;
strcpy(appearlist[i] -> word, word);
}
}