Question

我的查询：

SELECT DISTINCT V.COMPANY, V.VENDOR_NUM, V.VENDOR_PAYEE_NUM,
  C.CONTACT_NAME, C.CONTACT_AUDIT_DATE
  FROM
       VENDOR_TABLE AS V INNER JOIN CONTACT_TABLE AS C ON (V.COMPANY = C.COMPANY AND DIGITS(V.VENDOR_NUM) = C.VENDOR_NUM)
       WHERE DATE(INSERT(INSERT(DIGITS(V.VENDOR_AUDIT_DATE), 5, 0, '-'), 8, 0, '-    ')) >= DATE(VARCHAR_FORMAT(TIMESTAMP_ISO(CURRENT DATE), 'YYYY-MM-DD')) - 21 DAYS
       AND V.VENDOR_AUDIT_DATE <> 0 AND (V.STATUS = ' ' OR V.STATUS IS NULL)

它返回以下结果：

COMPANY   VENDOR_NUM  VENDOR_PAYEE_NUM V  CONTACT_NAME                    CONTACT_AUDIT_DATE
-------   ----------  ----------------    ------------------------------  ------------------
    908        13514             13514    Coleen                          20120427
    908        34242             34242    Frank Cheese                    20100120
    908        60148             60148    Sarah Lee/Jonh Doe              20141121
    908        60148             60148    Sarah Lee/Jonh Doe              20141121
    908        60151             60151    Sarah Lee/Jonh Doe              20140919
    908        60151             60151    Sarah Lee/Jonh Doe              20140919
    908        60152             60152    Sarah Lee/Jonh Doe              20140919
    908        60152             60152    Sarah Lee/Jonh Doe              20140919

联系人表格可能包含同一供应商的多个联系人。但是，我只想从供应商表中检索每个供应商编号的一个联系人。如何加入这些表，但只从供应商表中的每个供应商的Contact表中选择1个或不同的供应商联系人？

我稍微修改了我的查询。我发现联系表上有一个我可以操作的序列号。我需要该记录集中的最大序列。但是，我一直收到错误，＆＃34;列CZCO或SELECT列表中的表达式无效＆＃34;。我不确定我可能做错了什么......非常感谢任何帮助。

SELECT COMPANY, VENDOR_NUM, VENDOR_PAYEE_NUM,
  VENDOR_NAME, COUNTRY_CODE, ADDRESS_1,
  ADDRESS_2, CITY_STATE, ZIP_CODE,
  PAY_ADDR_1, PAY_ADDR_2, PAY_CITY_STATE,
  PAYEE_ZIP_CODE, VENDOR_AUDIT_DATE
  FROM VENDOR_TABLE V 
  INNER JOIN
  (
  SELECT CONTACT_KEY, COMPANY, CONTACT_PHONE,
  CONTACT_FAX, CONTACT_EMAIL, CONTACT_NAME,
  CONTACT_AUDIT_DATE, MAX(SEQ_NUM) AS SEQ_NUM
  FROM CONTACT_TABLE GROUP BY CONTACT_KEY
  ) C ON (V.COMPANY = C.COMPANY AND DIGITS(V.VENDOR_NUM) = C.CONTACT_KEY)
  WHERE DATE(INSERT(INSERT(DIGITS(V.VENDOR_AUDIT_DATE), 5, 0, '-'), 8, 0, '-')) >= DATE(VARCHAR_FORMAT(TIMESTAMP_ISO(CURRENT DATE), 'YYYY-MM-DD')) - 20 DAYS
    AND V.VENDOR_AUDIT_DATE <> 0 AND (V.STATUS = ' ' OR V.STATUS IS NULL)

Answer 1

一种方法是使用keep dense rank函数按某种方式分组并将其余部分保持在一起。

WITH sample_data AS (SELECT   908 AS company,
                    13514 AS vendor_num,
                    13514 AS vendor_payee_num,
                    'Coleen' AS contact_name,
                    20120427 AS contact_audit_date
             FROM   DUAL
           UNION ALL
           SELECT   908,
                    34242,
                    34242,
                    'Frank Cheese',
                    20100120
             FROM   DUAL
           UNION ALL
           SELECT   908,
                    60148,
                    60148,
                    'Sarah Lee/Jonh Doe',
                    20141121
             FROM   DUAL
           UNION ALL
           SELECT   908,
                    60148,
                    60148,
                    'Sarah Lee/Jonh Doe',
                    20141121
             FROM   DUAL
           UNION ALL
           SELECT   908,
                    60151,
                    60151,
                    'Sarah Lee/Jonh Doe',
                    20140919
             FROM   DUAL
           UNION ALL
           SELECT   908,
                    60151,
                    60151,
                    'Sarah Lee/Jonh Doe',
                    20140919
             FROM   DUAL
           UNION ALL
           SELECT   908,
                    60152,
                    60152,
                    'Sarah Lee/Jonh Doe',
                    20140919
             FROM   DUAL
           UNION ALL
           SELECT   908,
                    60152,
                    60152,
                    'Sarah Lee/Jonh Doe',
                    20140919
             FROM   DUAL)
  SELECT   company,
           vendor_num,
           vendor_payee_num,
           MIN (contact_name)
              KEEP (DENSE_RANK FIRST ORDER BY contact_name, contact_audit_date)
              contact_name,
           MIN (contact_audit_date)
              KEEP (DENSE_RANK FIRST ORDER BY contact_name, contact_audit_date)
              contact_audit_date
    FROM   sample_data
GROUP BY   company, vendor_num, vendor_payee_num



COMPANY VENDOR_NUM  VENDOR_PAYEE_NUM    CONTACT_NAME    CONTACT_AUDIT_DATE

908 13514   13514   Coleen  20120427
908 34242   34242   Frank Cheese    20100120
908 60148   60148   Sarah Lee/Jonh Doe  20141121
908 60151   60151   Sarah Lee/Jonh Doe  20140919
908 60152   60152   Sarah Lee/Jonh Doe  20140919

返回多个表的不同结果集 - DB2

1 个答案: