Question

所以这段代码一直有效，直到您决定点击Cancel或关闭输入框窗口，其中X为它提供：

运行时错误＆＃39; 424＆＃39;：

需要对象

然后它在debug中强调了这部分代码：

Set ranC = Application.InputBox("Select the Cal B table.", Type:=8)

我似乎无法使用零字符串长度字符串测试来取消此应用程序。我需要能够关闭当前工作簿，显示用户表单并退出子。

以下是我的代码:(只要您选择了某些内容并且不取消或关闭，代码就可以运行）

Sub popCheckVals()
Dim ranC As Range, calBC(1 To 39) As Variant, i As Integer, j As Integer, k As Integer, l As Integer
dozerCal.Hide

Set ranC = Application.InputBox("Select the Cal B table.", Type:=8)

l = 1
For j = 1 To 13
    For i = 1 To 3
        calBC(l) = ranC(j, i)
        l = l + 1
    Next
Next
 mltn = calBC(1)
 mlte = calBC(2)
 mltelev = calBC(3)
 rltn = calBC(4)
 rlte = calBC(5)
 rltelev = calBC(6)
 mrtn = calBC(10)
 mrte = calBC(11)
 mrtelev = calBC(12)
 rrtn = calBC(13)
 rrte = calBC(14)
 rrtelev = calBC(15)
 smltn = calBC(22)
 smlte = calBC(23)
 smltelev = calBC(24)
 srltn = calBC(25)
 srlte = calBC(26)
 srltelev = calBC(27)
 smrtn = calBC(31)
 smrte = calBC(32)
 smrtelev = calBC(33)
 srrtn = calBC(34)
 srrte = calBC(35)
 srrtelev = calBC(36)

    ActiveWorkbook.Close
    dozerCal.Show
End If
End Sub

Answer 1

当用户点击InputBox按钮False时，返回On Error Resume Next Set ranC = Application.InputBox("Select the Cal B table.", Type:=8) If Err.Number = 424 Then ' Handle cancel button Debug.Print "User cancelled" Exit Sub ElseIf Err.Number <> 0 Then ' Handle unexpected error Debug.Print "Unexpected error" Else ' Your code here End If On Error GoTo 0 ' This line could go in the else block，这不是Range对象，也不能分配给ranC。处理此问题的一种方法是将这部分代码包装在错误处理程序中：

CHECK(jsonb_typeof(foo)='object' AND foo<>'{}'::JSONB)

无法正确取消Application.Inputbox

1 个答案: