这是我下面的代码及其作用,将输入转换为变量string1,然后我的while循环标记每个单词,我能够达到我的作业的目标,即反转单词中的单词串。在我的代码下面是它的输出,正如你所看到的,没有空格。如何在最终字符串中添加类似于原始字符串的空格?
代码:
int main()
{
int ch, ss=0, s=0;
char x[3];
char *word, string1[100], string2[100], temp[100]={0};
x[0]='y';
while(x[0]=='y'||x[0]=='Y')
{
printf("Enter a String: ");
fgets(string1, 100, stdin);
if (string1[98] != '\n' && string1[99] == '\0') { while ( (ch = fgetc(stdin)) != EOF && ch != '\n'); }
word = strtok(string1, " \n");
while(word != NULL)
{
s = strlen(word);
ss=ss+s;
strncpy(string2, word, s+1);
strncat(string2, temp, ss);
strncpy(temp, string2, ss+1);
printf("string2: %s\n",temp);
word = strtok(NULL, " \n");
}
printf("Run Again?(y/n):");
fgets(x, 2, stdin);
while ( (ch = fgetc(stdin)) != EOF && ch != '\n');
}
return 0;
}
输出:
Enter a String: AAA BBB CCC
string2: AAA
string2: BBBAAA
string2: CCCBBBAAA
答案 0 :(得分:1)
如何简单地添加空格?
#include <stdio.h>
#include <string.h>
int main()
{
int ch, ss=0, s=0;
char x[3];
char *word, string1[100]={0}, string2[200], temp[200]={0};
x[0]='y';
while(x[0]=='y'||x[0]=='Y')
{
printf("Enter a String: ");
fgets(string1, 100, stdin);
if (string1[98] != '\n' && string1[99] == '\0') { while ( (ch = fgetc(stdin)) != EOF && ch != '\n'); }
word = strtok(string1, " \n");
while(word != NULL)
{
s = strlen(word);
ss=ss+s;
/* copy the word to the working buffer */
strncpy(string2, word, s+1);
/* if this is not the first word, put a space after the word */
if (temp[0] != '\0') strcat(string2, " "); /* add this */
/* concat the previously read words after the new word and a space */
strncat(string2, temp, ss);
/* adjust the length of the string for the added space */
ss++; /* add this for space */
/* copy the new result to temp */
strncpy(temp, string2, ss+1);
printf("string2: %s\n",temp);
word = strtok(NULL, " \n");
}
printf("Run Again?(y/n):");
fgets(x, 2, stdin);
while ( (ch = fgetc(stdin)) != EOF && ch != '\n');
}
return 0;
}