Question

抱歉我的英文。我创建自定义通知（使用parse.com和lib）。我希望这样：我收到通知 - ＆gt;点击这个 - ＆gt;开启新活动。我花了很多次来解决这个问题，但没有成功。我的代码：

public class Receiver extends ParsePushBroadcastReceiver {

    NotificationCompat.Builder mBuilder;
    int mNotificationId = 001;


    @Override
    public void onPushOpen(Context context, Intent intent) {
        ParseAnalytics.trackAppOpenedInBackground(intent);

        Intent i = new Intent(context, Main.class);
        i.putExtras(intent.getExtras());
        i.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
        context.startActivity(i);
    }


    @Override
    public void onReceive(Context context, Intent intent) {

        PendingIntent resultPendingIntent = PendingIntent.getActivity(context,
                0, intent, PendingIntent.FLAG_UPDATE_CURRENT);


        PowerManager pm = (PowerManager) context.getSystemService(Context.POWER_SERVICE);
        PowerManager.WakeLock wl = pm.newWakeLock(PowerManager.FULL_WAKE_LOCK | PowerManager.ACQUIRE_CAUSES_WAKEUP, "TAG");
        wl.acquire(15000);

        mBuilder = new NotificationCompat.Builder(context);
        mBuilder.setVibrate(new long[]{1000, 1000});
        mBuilder.setSmallIcon(R.drawable.icon); //You can change your icon
        mBuilder.setContentText("Content");
        mBuilder.setContentTitle("Title");
        mBuilder.setSound(Uri.parse("android.resource://" + context.getPackageName() + "/" + R.raw.beep1));
        mBuilder.setAutoCancel(true);

        mBuilder.setContentIntent(resultPendingIntent);

        NotificationManager notificationManager = (NotificationManager) context
                .getSystemService(context.NOTIFICATION_SERVICE);

        notificationManager.notify(mNotificationId, mBuilder.build());


    }
}

清单

<receiver android:name=".Receiver"
    android:exported="false">
    <intent-filter>
        <action android:name="com.parse.push.intent.RECEIVE" />
        <action android:name="com.parse.push.intent.DELETE" />
        <action android:name="com.parse.push.intent.OPEN" />
    </intent-filter>
</receiver>

Answer 1

我可以使用以下代码段打开预期的活动！

@Override
    protected void onPushOpen(Context context, Intent intent) {
        try {
            super.onPushOpen(context, intent);
            ParseAnalytics.trackAppOpenedInBackground(intent);
            PushService.setDefaultPushCallback(context, NewFragment.class);
            ParseAnalytics.trackAppOpenedInBackground(intent);
            Intent i = new Intent(context, NewFragment.class);
            i.putExtras(intent.getExtras());
            i.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK);
            context.startActivity(i);
        } catch (Exception e) {
            Log.d(TAG, "onPushOpen Error : " + e);
        }
    }

Answer 2

您可以启动一项新活动，该活动可以在sperate屏幕/布局上显示新通知。

为此，请转到ParseApplication.java

public class ParseApplication extends Application {
    @Override
    public void onCreate() {
        super.onCreate();
        Parse.initialize(this, keys.applicationId, keys.clientKey);
        PushService.setDefaultPushCallback(this, NewActivity.java);
        ParseInstallation.getCurrentInstallation().saveEventually();
    }

基本上，当您收到通知并且用户点击时，它会加载NewActivity.java，而NewActivity.java会打开xml文件。

现在NewActivity.java转到onCreate

中setContentView的{{1}}

setContentView(R.layout.**layout name**);

把你的xml文件。

不要忘记在清单中添加活动。

无法在thePushOpen（parse.com）上打开活动

2 个答案: