Question

我对VBA有些新意，我正在尝试创建一个Sub()来从不同的Excel工作簿中读取数据。它的工作原理是打开工作簿，从中读取，然后我想再次关闭工作簿。最后一部分是导致以下错误的原因：

运行时错误'9'：

下标超出范围

在尝试关闭文件时，我无法理解为什么会出现此错误。我希望你们能帮忙。如果我注释掉Close()部分......

，它就有效

代码

Option Explicit

Sub Test()
    Dim Path, Filename
    Dim sh1 As Worksheet, sh2 As Worksheet, sh3 As Worksheet, transmitWorkbook As Workbook, revieveWorkbook As Workbook

    'Define a variable for the workbook which is to recieve data
    Set revieveWorkbook = ActiveWorkbook

    Path = "C:\Test Folder\"
    Filename = "FileToReadFrom.xlsx"

    'Open workbook which is to transmit, if its not already open
    If Is_WorkBook_Open(Path & Filename) Then
        Set transmitWorkbook = Workbooks(Path & Filename)
    Else
        Set transmitWorkbook = Workbooks.Open(Path & Filename)
    End If

    revieveWorkbook.Sheets(1).Range("A1").Value = transmitWorkbook.Sheets(2).Range("F9").Value
    revieveWorkbook.Sheets(1).Range("B1").Value = Month(transmitWorkbook.Sheets(2).Range("H9").Value)

    Workbooks(Path & Filename).Close SaveChanges:=False


End Sub

Answer 1

正如Jeeped的评论中所提到的，路径名称不再用于关闭工作簿。正确的代码是

Workbooks(Filename).Close SaveChanges:=False

感谢大家的帮助。

Workbook.Close（）导致“运行时错误9”

1 个答案: