需要帮助构建SQL,通过订单表,它包含Date,SalesID,ItemID和其他misc。列。 表格如下:
Date SalesID ItemID
13-9-15 6:15:00 56 6
13-9-15 6:00:00 56 6
13-9-15 6:26:00 56 4
13-9-15 6:38:00 34 4
13-9-15 7:05:00 34 2
13-9-15 6:42:00 12 2
13-9-15 7:20:00 12 5
13-9-15 7:34:00 78 5
13-9-15 7:41:00 78 6
作为附加列,我想要的是,每当新SalesID按日期开始排序时,每个计数器都会递增。计数器列将计数直到最大值为3.我正在使用DENSE_RANK()对于增量列。
最后我需要的是:
Date SalesID ItemID Counter
13-9-15 6:00:00 56 6 1
13-9-15 6:15:00 56 6 1
13-9-15 6:26:00 56 4 1
13-9-15 6:38:00 34 4 2
13-9-15 6:42:00 34 2 2
13-9-15 7:05:00 12 2 3
13-9-15 7:20:00 12 5 3
13-9-15 7:34:00 78 5 1
13-9-15 7:41:00 78 6 1
答案 0 :(得分:0)
此解决方案适用于sqlserver 2012+。我必须更正示例中的无效数据才能获得正确的输出
DECLARE @t table(Date datetime, SalesID int, ItemID int)
INSERT @t values
('2015-09-13 6:15:00',56,6),
('2015-09-13 6:00:00',56,6),
('2015-09-13 6:26:00',56,4),
('2015-09-13 6:38:00',34,4),
('2015-09-13 6:42:00',34,2),
('2015-09-13 7:05:00',12,2),
('2015-09-13 7:10:00',12,5),
('2015-09-13 7:34:00',78,5),
('2015-09-13 7:41:00',78,6)
;WITH CTE as
(
SELECT
[Date], [SalesID], [ItemID],
CASE WHEN lag(SalesID) over (order by Date) = SalesID
THEN 0 ELSE 1 END x
FROM @t
)
SELECT
[Date], [SalesID], [ItemID],
(sum(x) over (ORDER BY Date) - 1) % 3 + 1 [Counter]
FROM CTE
结果:
Date SalesID ItemID Counter
2015-09-13 06:00 56 6 1
2015-09-13 06:15 56 6 1
2015-09-13 06:26 56 4 1
2015-09-13 06:38 34 4 2
2015-09-13 06:42 34 2 2
2015-09-13 07:05 12 2 3
2015-09-13 07:10 12 5 3
2015-09-13 07:34 78 5 1
2015-09-13 07:41 78 6 1
这适用于sqlserver 2008:
;WITH CTE as
(
SELECT
[Date],
SalesID,
ItemID,
row_number() over (order by Date)-
row_number() over (partition by SalesID order by Date) x
FROM @t
)
SELECT
[Date],
SalesID,
ItemID,
(dense_rank() over (order by x) - 1) % 3 + 1 [Counter]
FROM CTE