Question

我有两种类型：

BaseUser < ActiveRecord::Base

和

User < BaseUser

使用Authlogic的身份验证系统执行acts_as_authentic。此继承是使用单表继承

实现的

如果新用户注册，我将他注册为用户。但是，如果我已经有一个具有相同电子邮件的BaseUser，我想将该BaseUser更改为数据库中的用户，而不是简单地将所有数据从BaseUser复制到用户并创建新用户（即使用新用户） ID）。这可能吗？感谢。

Answer 1

史蒂夫的回答是有效的，但由于在调用BaseUser时实例属于类save，因此User中定义的验证和回调将无法运行。您可能希望使用becomes方法转换实例：

user = BaseUser.where(email: "user@example.com").first_or_initialize
user = user.becomes(User) # convert to instance from BaseUser to User
user.type = "User"
user.save!

Answer 2

您只需将类型字段设置为“用户”并保存记录即可。内存中对象仍将显示为BaseUser，但下次重新加载内存中对象时将是用户

>> b=BaseUser.new
>> b.class # = BaseUser

# Set the Type. In-Memory object is still a BaseUser
>> b.type='User'
>> b.class # = BaseUser
>> b.save

# Retrieve the records through both models (Each has the same class)

>> User.find(1).class # = User
>> BaseUser.find(1).class # User

Answer 3

基于其他答案，我预计这将在Rails 4.1中起作用：

  def update
    @company = Company.find(params[:id])
    # This separate step is required to change Single Table Inheritance types
    new_type = params[:company][:type]
    if new_type != @company.type && Company::COMPANY_TYPES.include?(new_type)
      @company.becomes!(new_type.constantize)
      @company.type = new_type
      @company.save!
    end

    @company.update(company_params)
    respond_with(@company)
  end

它没有，因为类型改变不会持续。相反，我选择了这种不太优雅的方法，它可以正常工作：

  def update
    @company = Company.find(params[:id])
    # This separate step is required to change Single Table Inheritance types
    new_type = params[:company][:type]
    if new_type != @company.type && Company::COMPANY_TYPES.include?(new_type)
      @company.update_column :type, new_type
    end

    @company.update(company_params)
    respond_with(@company)
  end

以下是我用来确认解决方案的控制器测试：

  describe 'Single Table Inheritance (STI)' do

    class String
      def articleize
        %w(a e i o u).include?(self[0].to_s.downcase) ? "an #{self}" : "a #{self}"
      end
    end

    Company::COMPANY_TYPES.each do |sti_type|
      it "a newly assigned Company of type #{sti_type} " \
        "should be #{sti_type.articleize}" do
        post :create, { company: attributes_for(:company, type: sti_type) },
             valid_session
        expect(assigns(:company)).to be_a(sti_type.constantize)
      end
    end

    Company::COMPANY_TYPES.each_index do |i|
      sti_type, next_sti_type = Company::COMPANY_TYPES[i - 1],
                                Company::COMPANY_TYPES[i]
      it "#{sti_type.articleize} changed to type #{next_sti_type} " \
        "should be #{next_sti_type.articleize}" do
        company = Company.create! attributes_for(:company, type: sti_type)
        put :update, { id: company.to_param, company: { type: next_sti_type } },
            valid_session
        reloaded_company = Company.find(company.to_param)
        expect(reloaded_company).to be_a(next_sti_type.constantize)
      end
    end
  end

使用单表继承更改Rails中的ActiveRecord类的类型

3 个答案: