Question

我正在编写一个简单的tkinter widget，其中包含一列输入框和一列按钮。该按钮应在相应的输入框中打印该值。我基本上编写了所有代码，但是我已经将行标签硬编码到我的函数中：

print find_in_grid(root, 2, 0).get()

我需要将2替换为单击按钮的行。我怎么能得到那一行？

整个代码：

from Tkinter import *

def print_value():
    print find_in_grid(root, 2, 0).get()


def find_in_grid(frame, row, column):
    for children in frame.children.values():
        info = children.grid_info()
        #note that rows and column numbers are stored as string
        if info['row'] == str(row) and info['column'] == str(column):
            return children
    return None

root = Tk()

height = 5
width = 1
for i in range(height): #Rows
    for j in range(width): #Columns
        b = Entry(root, text="", width=100)
        b.grid(row=i, column=j)

height = 5
width = 1
for i in range(height): #Rows
    for j in range(width): #Columns
        b = Button(root, text="print value", command=print_value, width=10)
        b.grid(row=i, column=j+1)


mainloop()

Answer 1

您可以将行和列值作为参数传递给print_value。绑定命令时不要忘记使用default variable trick，否则它总是认为你点击了右下角的按钮。

def print_value(row, col):
    print find_in_grid(root, row, col).get()

#...

height = 5
width = 1
for i in range(height): #Rows
    for j in range(width): #Columns
        b = Button(root, text="print value", command=lambda i=i,j=j: print_value(i,j), width=10)
        b.grid(row=i, column=j+1)

您也可以直接传入条目对象，但这需要进行一些重构：

from Tkinter import *

def print_value(entry):
    print entry.get()

root = Tk()

height = 5
width = 1
for i in range(height): #Rows
    for j in range(width): #Columns
        entry = Entry(root, text="", width=100)
        entry.grid(row=i, column=j)
        b = Button(root, text="print value", command= lambda entry=entry: print_value(entry), width=10)
        b.grid(row=i, column=j+1)

mainloop()

单击时在网格中获取tkinter按钮的行

1 个答案: