假设我有以下文件
{
_id: ObjectId("5234cc89687ea597eabee675"),
code: "xyz",
tags: [ "school", "book", "bag", "headphone", "appliance" ],
qty: [
{ size: "S", num: 10, color: "blue" },
{ size: "M", num: 45, color: "blue" },
{ size: "L", num: 100, color: "green" }
]
}
{
_id: ObjectId("5234cc8a687ea597eabee676"),
code: "abc",
tags: [ "appliance", "school", "book" ],
qty: [
{ size: "6", num: 100, color: "green" },
{ size: "6", num: 50, color: "blue" },
{ size: "8", num: 100, color: "brown" }
]
}
{
_id: ObjectId("5234ccb7687ea597eabee677"),
code: "efg",
tags: [ "school", "book" ],
qty: [
{ size: "S", num: 10, color: "blue" },
{ size: "M", num: 100, color: "blue" },
{ size: "L", num: 100, color: "green" }
]
}
我想将代码为“efg”的文档中所有元素的num更改为0.我该怎么办?我应该使用位置运算符的循环吗?
答案 0 :(得分:5)
执行此操作的最佳方法是匹配数组元素,并使用$
API单独更新位置Bulk()
运算符。你真的不应该吹你的qty
数组。
var bulk = db.mycollection.initializeOrderedBulkOp(),
count = 0;
db.mycollection.find({ "code" : "efg" }).forEach(function(doc){
var qty = doc["qty"];
for (var idx = 0; idx < qty.length; idx++){
bulk.find({
"_id": doc._id,
"qty": { "$elemMatch": { "num": qty[idx]["num"]}}
}).update({ "$set": { "qty.$.num": 0 }})
}
count++;
if (count % 200 == 0) {
// Execute per 200 operations and re-init.
bulk.execute();
bulk = db.mycollection.initializeOrderedBulkOp();
}
})
// Clean up queues
if (count % 200 != 0)
bulk.execute();