Question

如何简化下一个where子句？：

    where
        e.withdrawalMonth is null
        and ((:debt = 1 and not exists
            (from
            PaidConcept cc
                join cc.invoice i
             where
             cc.enrollment = e
             and cc.month = m
             and cc.concept = co
             and i.status = 'PAID'
            ))
         or(:debt = 0 and exists
            (from
            PaidConcept cc
                join cc.invoice i
             where
             cc.enrollment = e
             and cc.month = m
             and cc.concept = co
             and i.status = 'PAID'
            ))
        )

有两个相等的子查询，但第一个是not exists，第二个是exists我希望在debt参数为1时首先运行，在debt参数为0时最后运行

怎么可以做得更干？

Answer 1

String subquery = (from
            PaidConcept cc
                join cc.invoice i
             where
             cc.enrollment = e
             and cc.month = m
             and cc.concept = co
             and i.status = 'PAID'
            ))

String query = "where e.withdrawalMonth is null 
      + " and ((:debt = 1 and not exists "
      + subquery 
      + " or(:debt = 0 and exists " 
      + subquery + ")"

条件何处消除hql中的重复

1 个答案: