Question

我正在构建一个简单的记分牌。它基本上是公司中每个雇员引入外部用户（“推荐”）的总结清单。该列表只需通过对推荐的最后3个字母（=员工姓名首字母）进行分组来完成。但是，其中一名员工使用两种不同的推荐，我需要选择这两个推荐并将其总和为一个总和（因此我可以使用该值在我的记分板上排序）。

正常推荐看起来像这样：“％_ abc”。有问题的员工有两个推荐：“％_ xyz”和“RE％”。

这是当前的代码：

SELECT
    RIGHT(Referral, 3) [Referral], COUNT(*) [Total]
FROM TableName
WHERE
    CAST(Created AS DATE) = CAST(DATEADD(DAY, -1, GETDATE()) AS DATE)
    AND
    (
        Referral LIKE '%_abc'
        OR
        Referral LIKE '%_xyz'
        ...
    )
GROUP BY RIGHT(Referral, 3)
ORDER BY [Total] DESC

Answer 1

我用以下代码解决了我的问题。欢迎任何优化提示。

SELECT Referral, SUM(Total) AS Total FROM
(
    SELECT RIGHT(Referral, 3) [Referral], COUNT(*) [Total]
    FROM TableName
    WHERE
           CAST(Created AS DATE) = CAST(GETDATE() AS DATE)
        AND
        (
            Referral LIKE '%_abc'
            OR
            Referral LIKE '%_xyz'
            ...
        )
    GROUP BY RIGHT(Referral, 3)
    UNION ALL
    SELECT 'xyz' AS Referral, COUNT(*) [Total]
    FROM TableName
    WHERE
        CAST(Created AS DATE) = CAST(GETDATE() AS DATE)
        AND
        LEFT(Referral, 2) = 'RE'
) t
GROUP BY t.Referral
ORDER BY Total DESC

建立记分板 - 需要将两个不同推荐的值合并为一个总和

1 个答案: