我想开发一个使用JSON对象的动态菜单系统,因为我使用的是angular-fillter.js,但我无法获得正确的输出。
我期待这样说:
1.Topic
PAGE_NAME
- 类别
cate1
说明
cate2
descrption
- 子类别
SUB1
说明
SUB2
描述
我的app.js:
angular.module('app',['angular.filter'])
.controller('MainController', function($scope) {
$scope.items =
[{"$id":"1",
"userid":1,
"topic":"topic",
"topicOrderId":1,
"category":"cate1",
"catOrderId":1,
"subCategory":"sub1",
"subCatOrderId":1,
"page_Name":"page_Name1",
"pageId":1,
"url":"dashboard/index",
"description":"description1",
"tooltip":"topic1"},
{"$id":"2",
"userid":1,
"topic":"topic",
"topicOrderId":1,
"category":"cate1",
"catOrderId":1,
"subCategory":"sub2",
"subCatOrderId":1,
"page_Name":"page_Name2",
"pageId":1,
"url":"dashboard/index2",
"description":"description2",
"tooltip":"topic2"},
{"$id":"3",
"userid":1,
"topic":"topic",
"topicOrderId":1,
"category":"cate2",
"catOrderId":1,
"subCategory":"sub4",
"subCatOrderId":1,
"page_Name":"page_Name3",
"pageId":1,
"url":"dashboard/index3",
"description":"description3",
"tooltip":"topic4"},
{"$id":"4",
"userid":1,
"topic":"topic",
"topicOrderId":1,
"category":"cate3",
"catOrderId":1,
"subCategory":"sub3",
"subCatOrderId":1,
"page_Name":"page_Name4",
"pageId":1,
"url":"dashboard/index4",
"description":"description4",
"tooltip":"topic4"},
{"$id":"5",
"userid":1,
"topic":"topic",
"topicOrderId":1,
"category":"cate2",
"catOrderId":1,
"subCategory":"sub5",
"subCatOrderId":1,
"page_Name":"page_Name5",
"pageId":1,
"url":"dashboard2/index",
"description":"description5",
"tooltip":"topic5"}];
});
和我的html文件:
<div class="navbar-collapse collapse sidebar-navbar-collapse">
<ul class="nav navbar-nav" >
<div ng-repeat="(key, value) in items | groupBy: 'topic'" >
<label> {{key}} </label>
<li> {{value.pageName}} </li>
<ul style="list-style-type: none">
<div ng-repeat=" (key , val) in value | groupBy: 'category' ">
<label>{{key}}</label>
<li>
{{val.description}}
</li>
<ul style="list-style-type: none" >
<div ng-repeat="x in val">
<li>{{x.subCategory}} </li>
</div>
</ul>
</div>
</ul>
</div>
</ul>
</div>
这里我想按主题和组类别分组,逻辑工作正常但我无法打印page_Name的值,描述 请让我知道如何做到这一点