Question

我有一个数据库有一个＆＃39;字＆＃39; table（存储单词）我希望检索并将数据发送到另一个ViewController，但是我没有收到实际的单词，而是获得了id。

这是我的代码：

(void)getListData {

//tableData = [[NSMutableArray alloc]init];
sqlite3_stmt *statement;
NSArray *paths = NSSearchPathForDirectoriesInDomains(NSDocumentDirectory, NSUserDomainMask, YES);
NSString *documentsDirectory = [paths objectAtIndex:0];
NSString *path = [documentsDirectory stringByAppendingPathComponent:@"dexternotedb.sqlite"];

if (sqlite3_open([path UTF8String], &database) == SQLITE_OK) {
    WordListViewController *temp = APP_DELEGATE.wordListViewController;
    NSLog(@"word id %ld",(long)[temp.wordId integerValue]);

    NSString *sql=[NSString stringWithFormat:@"SELECT * FROM words WHERE word_id=\"%@\"",APP_DELEGATE.wordListViewController.wordId];
    const char *read_stmt = [sql UTF8String];
    NSLog(@"select query%@",sql);


    if(sqlite3_prepare_v2(database, read_stmt, -1, &statement, NULL) == SQLITE_OK){
        sqlite3_bind_int(statement, 1, [temp.wordId integerValue]);

       while(sqlite3_step(statement) == SQLITE_ROW) {
           NSString *word1 = [NSString stringWithUTF8String:(char *)sqlite3_column_text(statement, 0)];
           [word addObject:word1];
           NSString *meaning1 = [NSString stringWithUTF8String:(char *)sqlite3_column_text(statement, 0)];
           [meaning addObject:meaning1];

           NSString *sentence1 = [NSString stringWithUTF8String:(char *)sqlite3_column_text(statement, 0)];
           [Sentence addObject:sentence1];

       }


    sqlite3_finalize(statement);
} else {
            sqlite3_close(database);
            NSAssert1(0, @"Failed to open database with message '%s'.", sqlite3_errmsg(database));

}

Answer 1

首先：

不要使用“Select *”，因为您实际上并不知道列的顺序，而是使用列索引来访问它们。

所以你应该使用真实姓名“Select，id，word ....”

第二

所有列检索都指向相同的索引0：

[NSString stringWithUTF8String:(char *)sqlite3_column_text(statement, 0)];

这就是为什么你得到相同的数据（id），因为它只有第一个索引。因此，将其更改为正确的索引1,2,3 ......您将获得正确的数据..

使用此SQL（检查列名是否正确）

SELECT word_id, word, meaning, sentence FROM words WHERE word_id=\"%@\"

然后您可以使用sqlite3_column_text的正确索引：

NSString *word1 = [NSString stringWithUTF8String:(char *)sqlite3_column_text(statement, 1)];
           [word addObject:word1];
           NSString *meaning1 = [NSString stringWithUTF8String:(char *)sqlite3_column_text(statement, 2)];
           [meaning addObject:meaning1];

           NSString *sentence1 = [NSString stringWithUTF8String:(char *)sqlite3_column_text(statement, 3)];
           [Sentence addObject:sentence1];

ViewController接收ID而不是SQLite查询中的数据

1 个答案: