没有得到以下代码的输出

Question

以下代码通过在其字符的ASCII值中添加4来转换编码消息，例如：A - ＆gt; D，M - ＆gt; p，代码区分大小写。

    var convertCode = function (sample) {
        var newArray = sample.split(""); //converting string to array//
        var x = newArray.length;
        var testArray = [];
        var resultArray = [];

        for (var i = 0; i < x; i++) {
            testArray.push(newArray[i].charCodeAt(0)); //conversion of characters to ASCII values//
            testArray[i] = testArray[i] + 4; //ADD 4 to ASCII values

            if (testArray[i] > 90 && testArray[i] <= 94) { //condition to keep uppercase alphabets within range//
                testArray[i] = testArray[i] - 90 + 65;
            } else if (testArray[i] > 122 && testArray[i] <= 126) { //condition to keep lowercase alphabets within range//
                testArray[i] = testArray[i] - 122 + 97;
            }

            resultArray.push(string.fromCharCode(testArray[i]));
            //converting the new Ascii values back to string//
        }
        resultArray.join(); //conversion of array back to string//
        alert(resultArray);
    };
    convertCode("ABCDE");

Answer 1

在您的代码中，您使用了被视为变量的string，在运行程序时，您将获得string is not defined，实际上您正在寻找＆＃39; String＆＃39;类而不是变量。

resultArray.push(String.fromCharCode(testArray[i]));

而不是

resultArray.push(string.fromCharCode(testArray[i]));

另外，添加3代替4将A转为D

testArray[i] = testArray[i] + 4;