Question

我这里的代码不会更新。如果我在输入文本中输入任何内容并按提交，那么＆＃39; samp.php＆＃39;仍会显示我已更新的数据库的原始信息。

index.php的代码

<?php
include 'connect.php';
?>
<html>
  <head>
  <title>Basic Form Handling PHP</title>
  </head>
  <body>
  <?php
$result1 = $db->query("select * from chapter where chapter_id='1'");
while($row1 = mysqli_fetch_assoc($result1)){ echo "<form action='samp.php' method='POST'>";
 echo "     <input class='input' type='hidden' name='cid' value='{$row1['chapter_id']}'/>";
 echo "       Title: <br>";
 echo "       <input type='text' name='ctitle'><br>";
 echo "       Body: <br>";
 echo "       <input type='text' name='cbody'><br>";
 echo "       <input type='submit' name='submit' value='PRESS ME'>";
 echo "   </form>";
}
  ?>
  </body>
</html>

connect.php的代码

<?php
$db = new mysqli('localhost', 'root', '2830775', 'unity');
?>

代码为samp.php

<?php
include 'connect.php';
?>
<?php
$id = $_POST['cid'];
$title = $_POST['ctitle'];
$body = $_POST['cbody'];
$result = $db->query("UPDATE chapter set chapter_title='$title', chapter_body='$body' where chapter_id='$id");
$result2 = $db->query("SELECT * FROM chapter where chapter_id='$id'");
?>
<?php $row1 = mysqli_fetch_assoc($result2);
 echo $row1['chapter_body']; 

 ?>

Answer 1

您需要将连接文件包含在same.php

中

   <?php
    include 'connect.php';// incliude your connection file
    $id = $_POST['cid'];
    $title = $_POST['ctitle'];
    $body = $_POST['cbody'];
    $result = $db->query("UPDATE chapter set chapter_title='$title', chapter_body='$body' where chapter_id = '$id'");//missing Singal quote in end 
    $result2 = $db->query("SELECT * FROM chapter where chapter_id='$id'");
?>
<?php
    $row1 = mysqli_fetch_assoc($result2);
    echo $row1['chapter_body'];

?>

Answer 2

将$result = $db->query("UPDATE chapter set chapter_title='$title', chapter_body='$body' where chapter_id='$id")更新为$result = $db->query("UPDATE chapter set chapter_title='$title', chapter_body='$body' where chapter_id='$id'")

你忘了在那里结束单引号。

PHP不会更新Mysql

2 个答案: