Question

我有一个问题，而我正在迭代Thymeleaf中的一个对象列表。这是我的HTML：

<input th:each="a,iterStatus : currentQuestion.answers" type="radio" name="answer" th:text="${a.answer}" th:value="${iterStatus.index}"></input>

这是Controller类：

@RequestMapping(value={ "/exam", "/exam/" }, method = RequestMethod.GET)
public String exam(Model model){

    if (!sessionPreferences.isExamStarted()){
        sessionPreferences.setQuestionList(questionService.list(Questions.findAll().paginate(0, 5).loadWith("answers")));
        sessionPreferences.setCurrentQuestion(questionService.uniqueObject(Questions.findAll().withId(1L).loadWith("answers")));
    }
    model.addAttribute("currentQuestion", sessionPreferences.getCurrentQuestion());
    sessionPreferences.setExamStarted(true);
    System.out.println("TRUE!");
    System.out.println(sessionPreferences.getCurrentQuestion().getAnswers().size());
    System.out.println(sessionPreferences.getCurrentQuestion().getAnswers().get(0));
    return "exam";
}

这是SessionPreferences类：

@Component
@Scope(value="session", proxyMode = ScopedProxyMode.TARGET_CLASS)
public class SessionPreferences implements Serializable {

private static final long serialVersionUID = -3875093750700352970L;

@Setter
private String displayName;

@Setter @Getter
private Question currentQuestion;

@Getter @Setter
private boolean examStarted;

@Getter @Setter
private Map<Question, Integer> selections = new LinkedHashMap<Question, Integer>();

@Getter @Setter
private List<Question> questionList = new ArrayList<Question>(5);


public String getDisplayName() {
    if(StringUtils.isBlank(displayName)){
        displayName = SecurityUtils.getLoggedUsername();
    }
    return displayName;
  }
}

我们有问题模型类：

@Entity
@Table(name = "questions")
public class Question extends BaseEntity<Long> {

private static final long serialVersionUID = -7066617446892759711L;
public static final int DESCRIPTION_MAX_LENGTH = 5120;
public static final int OPTIONS_MAX_LENGTH = 4 * 5120;

public Question() {
};

public Question(String questionDescription, List<Answer> answers) {
    this.questionDescription = questionDescription;
};

@Id
@GeneratedValue
@Getter
@Setter
private Long id;

@Getter
@Setter
@Column(length = DESCRIPTION_MAX_LENGTH, nullable = false, name = "question_description")
private String questionDescription;

@Getter
@Setter
@OneToMany(mappedBy = "question", targetEntity = Answer.class, cascade = CascadeType.ALL)
private List<Answer> answers = new ArrayList<>();

@Getter
@Setter
@Column(nullable = false, name = "correct_answer_id")
private Answer correctAnswerIndex;
}

答案课：

@Entity
@Table(name="answers")
public class Answer extends BaseEntity<Long>{

private static final long serialVersionUID = -6119650375719671237L;

public Answer(){};

public Answer(String answer){
    this.answer = answer;
};

@Id
@GeneratedValue
@Getter @Setter
private Long id;

@Getter @Setter
private String answer;

@ManyToOne
@JoinColumn(name = "question_id", updatable=false)
@Getter @Setter
private Question question;

}

DAO层和服务层工作正常，因此在使用Thymeleaf进行迭代时访问Answer对象中的String answer是个问题。

我有以下错误：

SEVERE: Servlet.service() for servlet [spring] in context with path [] threw exception [Request processing failed; nested exception is org.thymeleaf.exceptions.TemplateProcessingException: Exception evaluating SpringEL expression: "a.answer" (exam:99)] with root cause
  org.springframework.expression.spel.SpelEvaluationException: EL1008E:(pos 2): Field or property 'answer' cannot be found on object of type 'java.lang.String'

任何想法???

P.s三个syso导致：TRUE！，4，Object ..

Answer 1

th:each属性的语法存在问题，因为currentQuestion.answers应该包含在表达式评估（${...}）组中。

正确的版本：

<input th:each="a,iterStatus : ${currentQuestion.answers}" type="radio" name="answer" th:text="${a.answer}" th:value="${iterStatus.index}"></input>

Thymeleaf迭代对象列表

1 个答案: