Question

我有一个像：[(15932, 2.9, 1), (15430, 3.6, 0), (16712, 10.9, 1), (15890, 6.6, 1)]这样的元组列表，如何将其转换为以下DataFrame结构：

15932 2.9 1 

15430 3.6 0 

16712 10.9 1 

15890 6.6 1

Answer 1

这样简单，使用默认构造函数。

pd.DataFrame.from_records([(15932, 2.9, 1), (15430, 3.6, 0), (16712, 10.9, 1), (15890, 6.6, 1)])

或者使用替代构造函数。

awk 'BEGIN{FS=OFS=","; out=ARGV[1] ".removed.index"}
FNR==NR {
   for (i=1; i<=NF; i++)
      sums[i] += $i;
   ++r;
   next
} FNR==1 {
   for (i=3; i<=NF; i++) {
      if (sums[i] == 0) {
         if (i-1 in sums) {
            delete sums[i-1];
            print "removed index: " (i-1) > out
         }
         delete sums[i];
         print "removed index: " i > out
      } else if (sums[i] == 100*r) {
         delete sums[i];
         print "removed index: " i > out
      }
   }
} {
   printf "%s", $1
   for (i=2; i<=NF; i++)
      if (i in sums)
         printf "%s%s", OFS, $i;
   printf "%s", ORS
} END{close(out)}' file file

Python：如何将元组列表转换为DataFrame

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