我有一种情况,我不知道我是否正确接近,但在这里:我想要发生第二次POST,但前提是第一次POST说好了。
function save_match(slot, save) {
listItems.each(function(idx, li) {
var player = $(li);
if(i >= 0) {
// do some work
} else {
// post that should prevent second post from executing, depending on `return_msg`
$.post(..., function(return_msg) {
if(return_msg == "not_ok") {
// I did this in hope that it will do the trick, but no
location.reload();
}
}
);
}
});
// do a little work
$.ajax({
...
});
}
我试图设置一个繁忙的循环,但这会冻结浏览器。我想让第一个POST调用同步(但是它不会让//do some work
执行,直到POST返回,在93%它返回ok
,但我不能看另一个选择,如果可以的话,请告诉我),这样如果第一个电话的回复不合适,第二个POST就不会发生。
所以,我发现了这个问题:how to make a jquery “$.post” request synchronous,它说它的最佳答案已被弃用,并提供了阻止用户界面的内容。但是,我想阻止代码执行第二次调用!
2015年如何做到这一点?
答案 0 :(得分:1)
一种方法是使ajax同步,这是不推荐的。您可以在ajax电话上设置async: false
。
另一种方法是将一个ajax请求放入另一个的成功回调中。一个简单的例子是:
$.ajax({
url: "ajaxUrl",
type: "post",
success: function (data) {
if (data == "OK") {
//do other ajax
}
else {
}
},
error: function (jqxhr) { }
});
根据您的情况,上面的例子可能已经足够了。要获得更强大和可扩展的解决方案,您可以使用jQuery.Deferred。一个简单的例子:
var def = $.Deferred(); //Create $.Deferred;
$.ajax({
url: "ajaxUrl",
type: "post",
success: function (data) {
if (data == "OK")
def.resolve(); //Let deferred know it was resolved with success
else
def.reject(); //Let deferred know it ended in a failure
},
error: function (jqxhr) { }
});
def.done(function () {
//this will only run when deferred is resolved
}).fail(function(){
//this will only run when deferred is rejected
}).always(function(){
//this will run when deferred is either resolved or rejected
})
答案 1 :(得分:1)
你警告"错误!"当return_msg
不等于not_ok
时。如果邮件是ok
或not_ok
,那就是您希望发布第二篇文章,并且您似乎已经知道如何发帖。
$.post(..., function(return_msg) {
// check for the success, as null or something else would be an error too
if(return_msg == "ok") {
// This is where you would do another post
$.post(..., function() {});
} else {
// This is where the error should be.
}
}
);