Question

这是我的xml结构

<catalog>
    <course>
        <course_id></course_id>
        <subjects>
            <subject>
                <subject_id></subject_id>
            </subject>
            <subject>
                <subject_id></subject_id>
            </subject>
        </subjects>
    </course>
</catalog>

所以，我试图使用JAXB Unmarshalling将这个xml绑定到一个类，但结果却没有。

我在想，我有2个基本元素，课程和主题，所以我根据这些元素构建了2个类这是为了控制课程标签

@XmlRootElement(name="catalog")
@XmlAccessorType(XmlAccessType.FIELD)
public class curso {
    @XmlElement(name="course_id")
    int course_id;

    @XmlElementWrapper(name="subjects")
    @XmlElement(name="subject")
    List <subject> subjects = new ArrayList<>();


    public void setCourse_id(int curso_id) {
        this.curso_id = curso_id;
    }

    public void setSubjects(List<subject> subjects) {
        this.subjects = subjects;
    }

}

这是为了控制主题标签。

public class subject {
    String subject_id;

    @XmlElement(name="subject_id")
    public void setSubjectId(String id) {
        this.subject_id = id;
    }
}

我做了一些字符串函数，我的输出什么都没有。有什么问题？

Answer 1

course元素还有一个包装标记<course>因此，您需要更改xml以删除<catalog>标记并将<course>作为根。或者您应该创建一个新的类目录并将课程作为一个字段。像

@XmlRootElement(name="catalog")
@XmlAccessorType(XmlAccessType.FIELD)
class catalog {
    @XmlElement(name="course")
    curso course;

    public curso getCourse() {
        return course;
    }

    public void setCourse(curso course) {
        this.course = course;
    }

    @Override
    public String toString() {
        return "catalog [course=" + course + "]";
    }
}

一个完整的例子

import java.io.File;
import java.util.ArrayList;
import java.util.List;

import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Unmarshaller;
import javax.xml.bind.annotation.XmlAccessType;
import javax.xml.bind.annotation.XmlAccessorType;
import javax.xml.bind.annotation.XmlElement;
import javax.xml.bind.annotation.XmlElementWrapper;
import javax.xml.bind.annotation.XmlRootElement;

@XmlRootElement(name="catalog")
@XmlAccessorType(XmlAccessType.FIELD)
class catalog {
    @XmlElement(name="course")
    curso course;

    public curso getCourse() {
        return course;
    }

    public void setCourse(curso course) {
        this.course = course;
    }

    @Override
    public String toString() {
        return "catalog [course=" + course + "]";
    }
}

class curso {
    @XmlElement(name = "course_id")
    int course_id;

    @XmlElementWrapper(name = "subjects")
    @XmlElement(name = "subject")
    List<subject> subjects = new ArrayList<>();

    public void setCourse_id(int curso_id) {
        this.course_id = curso_id;
    }

    public void setSubjects(List<subject> subjects) {
        this.subjects = subjects;
    }

    @Override
    public String toString() {
        return "curso [course_id=" + course_id + ", subjects=" + subjects + "]";
    }

}

class subject {
    String subject_id;

    @XmlElement(name = "subject_id")
    public void setSubjectId(String id) {
        this.subject_id = id;
    }

    @Override
    public String toString() {
        return "subject [subject_id=" + subject_id + "]";
    }
}

public class JaxbExample2 {
    public static void main(String[] args) {
        try {

            File file = new File("file.xml");
            JAXBContext jaxbContext = JAXBContext.newInstance(catalog.class);

            Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
            catalog customer = (catalog) jaxbUnmarshaller.unmarshal(file);
            System.out.println(customer);

        } catch (JAXBException e) {
            e.printStackTrace();
        }

    }
}

JAXB具有相同名称的解组元素

1 个答案: