Question

我有这样的查询：

 select ItemCode,ItemDescription,
  CASE
    WHEN dbo.T_Item_Movement.F_Status = 1 AND
      dbo.T_Item_Movement.F_Site_Code <> dbo.T_Item_Movement.F_Frm_Site_Code THEN SUM(dbo.T_Item_Movement.F_Quantity)
    ELSE 0
  END,
  CASE
    WHEN dbo.T_Item_Movement.F_Status = 2 AND
      dbo.T_Item_Movement.F_Site_Code <> dbo.T_Item_Movement.F_Frm_Site_Code THEN SUM(dbo.T_Item_Movement.F_Quantity)
    ELSE 0
  END
   from T_Item_Movement where F_Site_Code='12004'
   group by ItemCode,ItemDescription,T_Item_Movement.F_Status,T_Item_Movement.F_Site_Code,T_Item_Movement.F_Frm_Site_Code

我这样说：

itemcod       description               nocolumnname   nocolumnname
TT015-BLK   BLACK WOODEN TOP - ROUND    6                0
TT015-BLK   BLACK WOODEN TOP - ROUND    0                 5

而不是这个，我想这样出来：

 itemcod       description               nocolumnname   nocolumnname
    TT015-BLK   BLACK WOODEN TOP - ROUND    6            5

Answer 1

您可以使用条件聚合。

 select itemcode, itemdescription, max(somecol1), max(somecol2)
 from ( 
 select ItemCode,ItemDescription,
  CASE
    WHEN dbo.T_Item_Movement.F_Status = 1 AND
      dbo.T_Item_Movement.F_Site_Code <> dbo.T_Item_Movement.F_Frm_Site_Code THEN SUM(dbo.T_Item_Movement.F_Quantity)
    ELSE 0
  END as somecol1,
  CASE
    WHEN dbo.T_Item_Movement.F_Status = 2 AND
      dbo.T_Item_Movement.F_Site_Code <> dbo.T_Item_Movement.F_Frm_Site_Code THEN SUM(dbo.T_Item_Movement.F_Quantity)
    ELSE 0
  END as comecol2
   from T_Item_Movement 
   where F_Site_Code='12004'
   group by 
   ItemCode,ItemDescription,T_Item_Movement.F_Status,
   T_Item_Movement.F_Site_Code,T_Item_Movement.F_Frm_Site_Code
   ) t
   group by itemcode, itemdescription

Answer 2

当itemdescription匹配时，您似乎想要最早的ItemCode，并且您想要在评估其是否满足1或2状态后对其进行求和，不要计算它们。

SELECT min(itemCode) as ItemCode
 ,ItemDescription
 ,sum(case when FStatus=1 then 1 else 0 end) as in
 ,sum(case when FStatus=2 then 1 else 0 end) as out
FROM tableName
GROUP BY itemDescription

使用case语句如何计算

2 个答案: