Question

我可以处理404错误。

@ResponseStatus(value = HttpStatus.NOT_FOUND)
    @ExceptionHandler(NoHandlerFoundException.class)
    @ResponseBody
    public void noHandlerFoundException (HttpServletResponse response) throws IOException{
       //some code
    }

但是如何处理401错误？

编辑我使用的是Java而不是web.xml

编辑我应该在NoHandlerFoundException中放置什么来处理HttpStatus.UNAUTHORIZED

修改

当身份验证失败时，我的方法失败了身份验证：

public class StatelessLoginFilter extends AbstractAuthenticationProcessingFilter { 

    protected void unsuccessfulAuthentication(HttpServletRequest request, HttpServletResponse response,
                                                      AuthenticationException failed) throws IOException, ServletException {
                SecurityContextHolder.clearContext();

                if (logger.isDebugEnabled()) {
                    logger.debug("Authentication request failed: " + failed.toString());
                    logger.debug("Updated SecurityContextHolder to contain null Authentication");
                    logger.debug("Delegating to authentication failure handler " + failureHandler);
                }

        //        response.setCharacterEncoding("UTF-8");
        //        response.getWriter().write(jsonService.toString(jsonService.getResponse(false, "Не удалось авторизоваться", "401")));

                rememberMeServices.loginFail(request, response);
                failureHandler.onAuthenticationFailure(request, response, failed);

            }
        }

此代码发送了401错误html。我需要发送json，你可以在评论中看到它。

Answer 1

以下是所有错误页面集合的完整处理程序：

error

基础控制器：

@Controller
public class ErrorCodeController extends BaseController {

    @ExceptionHandler(ApplicationException.class)
    @RequestMapping(value="errorPage400", method=RequestMethod.GET)
    @ResponseStatus(value = HttpStatus.BAD_REQUEST)
    public String handleBadRequest(ApplicationException ex,HttpServletResponse response, ModelMap map) { 
        map.addAttribute("http-error-code", HttpStatus.BAD_REQUEST);
        return processErrorCodes(ex,response,map);
    }


    @ExceptionHandler(ApplicationException.class)
    @RequestMapping(value="errorPage401", method=RequestMethod.GET)
    @ResponseStatus(value=HttpStatus.UNAUTHORIZED,reason="Unauthorized Request")
    public String handleUnauthorizedRequest(ApplicationException ex,HttpServletResponse response, ModelMap map) { 
        map.addAttribute("http-error-code", HttpStatus.UNAUTHORIZED);
        return processErrorCodes(ex,response,map);
    }


    @ExceptionHandler(ApplicationException.class)
    @RequestMapping(value="errorPage404", method=RequestMethod.GET)
    @ResponseStatus(HttpStatus.NOT_FOUND)
    public String handleNotFoundRequest(ApplicationException ex,HttpServletResponse response, ModelMap map) { 
        map.addAttribute("http-error-code", HttpStatus.NOT_FOUND);
        return processErrorCodes(ex,response,map);
    }


    @ExceptionHandler(ApplicationException.class)
    @RequestMapping(value="errorPage500", method=RequestMethod.GET)
    @ResponseStatus(value=HttpStatus.INTERNAL_SERVER_ERROR,reason="Internal Server Error")
    public String handleInternalServerError(ApplicationException ex,HttpServletResponse response, ModelMap map) { 
        map.addAttribute("http-error-code", HttpStatus.INTERNAL_SERVER_ERROR);
        return processErrorCodes(ex,response,map);
    }

    @ExceptionHandler(ApplicationException.class)
    public void handleApplicationExceptions(Throwable exception, HttpServletResponse response) {

    }

    private String processErrorCodes(ApplicationException ex,HttpServletResponse response, ModelMap map){
        map.addAttribute("class", ClassUtils.getShortName(ex.getClass()));
        map.addAttribute("message", ex.getMessage());
        map.addAttribute("errorMessage", ex.getErrorMessage());
        map.addAttribute("errorCode", ex.getErrorCode());
        map.addAttribute("timestamp", ex.getCurrentDate());
        return "errorPage";
    }


}

Web.xml：

@Controller
@RequestMapping("/")
public class BaseController {

    // Remember to add any exception that you suspect can be thrown in this web application.


@ExceptionHandler({ApplicationException.class,NullPointerException.class})
    public ModelAndView handleException(Throwable exception,HttpServletRequest req) {

        ModelMap model = new ModelMap();
        ApplicationException ex = new ApplicationException();
        String timeStamp = ex.getCurrentDate().toString();
        //String temp = ClassUtils.getShortName(ex.getClass());
        //model.addAttribute("class", ClassUtils.getShortName(ex.getClass()));
        model.addAttribute("timeStamp", timeStamp);
        return new ModelAndView("errorPage", model);
    }

Answer 2

我知道这是一个古老的话题，但我也是如此，所以这里的解决方案只适用于Tomcat。

使用*DispatcherServletInitializer / WebAppInitializer #onStartup(...)方法调用以下方法。

Field appContextInFacade = ApplicationContextFacade.class.getDeclaredField("context");
appContextInFacade.setAccessible(true);
ApplicationContext appContext = (ApplicationContext) appContextInFacade.get(servletContext);
Field appContextInContext = ApplicationContext.class.getDeclaredField("context");
appContextInContext.setAccessible(true);
StandardContext context = (StandardContext) appContextInContext.get(appContext);
ErrorPage defaultErrorPage = new ErrorPage();
defaultErrorPage.setLocation("/myinternalerrorhandlercontroller");
context.addErrorPage(defaultErrorPage); // You may have to use reflection here as well.

然后添加一个能够处理这些错误请求的控制器：

@RequestMapping("/myinternalerrorhandlercontroller")
public ResponseEntity<T> renderErrorPage(HttpServletRequest httpRequest)

您可以使用以下方式提取错误详细信息：

(Integer) httpRequest.getAttribute(RequestDispatcher.ERROR_STATUS_CODE);

重要提示：

您必须处理所有RequestMethod s。
您必须处理所有Content-Type s（=＆gt;返回字节或注册后备HttpMessageConverter，无论请求的内容如何，都可以将您的错误对象转换为json。）
您的错误页面绝不能抛出异常或无法返回响应。
只有在未调用通常的@ExceptionHandler或类似机制或（无法执行）时才会显示错误页面。
不要访问您的应用程序状态，例如用户身份验证，因为您不在其范围内，并且可能无法使用或包含无效数据。

Answer 3

您可以查看

HttpStatus.UNAUTHORIZE

请参阅： Infos about HttpStatus (Spring Framework)

处理401错误（Spring Security）

3 个答案: