Question

我有这个问题：

declare @docId as varchar(36)    
declare @totalId AS VARCHAR(500)     
declare @C5 as int    
declare @bool as bit    

set @bool =1    
set @docId='fba18752-1a70-4413-bc3f-9390eaf8a7ef'    
set @totalId='''95B3F02C-8EBD-402E-9721-268A02830678'''+','+'''0211CFA9-1957-4C46-A6BE-16F7B5D8C50F'''

print @totalId

SELECT @C5=COUNT(*) FROM tblSend WHERE senDocId= @docId AND senReceiverDepartmentId IN (@totalId) AND senStatus in (3110,3125,3121) AND senReadDocument IN (0,2)

并有以下错误：

Msg 8169, Level 16, State 2, Line 15    
Conversion failed when converting from a character string to uniqueidentifier.

但是当我把@totalId值而不是它的变量时，它会像这样返回：

 SELECT @C5=COUNT(*) FROM tblSend WHERE senDocId= @docId AND senReceiverDepartmentId IN ('95B3F02C-8EBD-402E-9721-268A02830678','0211CFA9-1957-4C46-A6BE-16F7B5D8C50F') AND senStatus in (3110,3125,3121) AND senReadDocument IN (0,2)

为什么？

Answer 1

因为IN要求单个或逗号分隔的值与列值匹配。您在IN内证明的值为'SomeX,SomeY'。 SQL Server试图在'SomeX,SomeY'中查找senReceiverDepartmentId值，在此过程中，它尝试将'SomeX,SomeY'转换为GUID（源列数据类型）。这导致无效的转换错误。

您希望在 IN 中使用 'SomeX'，'SomeY' 您实际使用的是 'SomeX,SomeY'

尝试使用表变量并在其中插入ID并将其与IN组合使用。

    declare @docId as varchar(36)    
    DECLARE @totalId AS VARCHAR(500)   
    declare @C5 as int  
    declare @bool as bit  
    set @bool =1

    set @docId='fba18752-1a70-4413-bc3f-9390eaf8a7ef'

    DECLARE @totalIds TABLE(id varchar(100))

    INSERT INTO  @totalIds 
    VALUES
    ('95B3F02C-8EBD-402E-9721-268A02830678'),
    ('0211CFA9-1957-4C46-A6BE-16F7B5D8C50F')

    print @totalId

    SELECT @C5=COUNT(*) 
    FROM tblSend
    WHERE senDocId= @docId 
      AND senReceiverDepartmentId IN (select id from @totalIds) 
      AND senStatus in (3110,3125,3121) AND senReadDocument IN (0,2)

希望这是有道理的。

tsql＆＃34; in＆＃34;不归还任何东西

1 个答案: