Question

代码以JSON格式返回数据，它包含大约十个值，其中一个值称为state。我想创建函数来比较状态的返回值，例如，如果state = one show image1并且state = 2 show image2。怎么做？

JQuery url

var RealDataApi = function () {
var url_getgatedata = "api/realdata/getgatedata";

// public functions
return {
    getGateData: function (done, fail, always) {
        var jqxhr = $.get(url_getgatedata);
        jqXhrHandler(jqxhr, done, fail, always);
    },

JSON数据：

{"gateNo":1,"fullOpen":false,"fullClose":false,"opening":false,"closing":false,"mode":null,"state":null,"cond":null,"positionM":null,"positionP":null}

Answer 1

FIDDLE

getParameterByName(data);//get parameter name state


function getParameterByName(data) {
    if (data.state == '2') {
        alert('2');
    } else {
        alert(data.state);
    }
}

命名为json数据，然后你可以获得像data.state这样的状态值，然后将它与你想要比较的值进行比较

Answer 2

请试试这个：

if (jqxhr.state == 1) {
    //Do whatever you wanna do...
} else if (jqxhr.state == 2) {
    //Do whatever you wanna do...
}

Answer 3

对json响应使用eval：

function getState(data)
{
    if(data.state==1)
        return "image1";
    else if(data.state==2)
        return "image2";
} 

var jqxhr=eval({"gateNo":1,"fullOpen":false,"fullClose":false,"opening":false,"closing":false,"mode":null,"state":1,"cond":null,"positionM":null,"positionP":null});//parse as js object or eval($.get(url_getgatedata));
alert(getState(jqxhr));

比较JSON中返回的参数值

3 个答案: