Question

我是编程世界的新手，我开始运行一些非常基本的代码，但遇到了麻烦。我正在尝试使用gcc在Linux上运行它，但它不起作用，是否有人能够告诉我我正在做什么错误？

#include <stdio.h>

int main(){

    char letter;
    int grade1;
    int grade2;
    float grade3;
    float grade4;

    letter=Y
    grade1=98
    grade2=76
    grade3=67.5
    grade4=80.5

    printf("Please enter the first letter of your name:%c\n",letter);
    printf("Please enter the grade for your first test:%d\n",grade1);
    printf("Please enter the grade for your second test:%d\n",grade2);
    printf("Please enter the grade for your final test:%f\n",grade3);
    printf("The average mark:%f",grade4);

    return 0;

}

非常感谢任何帮助！

Answer 1

letter=Y
grade1=98
grade2=76
grade3=67.5
grade4=80.5

在每个陈述后你都需要一个分号。此外，Y需要使用单引号，因为它是您要分配给变量的字符，而不是变量本身：letter = 'Y'。

printf("Please enter the first letter of your name:%c\n",letter);

printf用于显示内容，scanf是您想要阅读的内容。所以你需要这样的东西：

printf("Please enter the first letter of your name:\n");
scanf("%c", &letter);

我建议从一本书或tutorial开始。

Answer 2

我建议您使用IDE，因为它会标记并在这种情况下立即给出关于缺失的半冒号的错误。

Visual Studio非常适合Windows，也有免费版本，对于linux，你可以在这里查看：C++ IDE for Linux?

此外，您应该谷歌您不熟悉的每个功能，并检查其示例以确保正确使用。

Answer 3

你的错误：

char letter='Y'//if you want to initialize letter variable  

//no need to enter the letter from the user because you initialized above 
// printf("Please enter the first letter of your name:%c\n",letter);

//otherwise you can get the value of letter variable using printf and scanf
char letter;  
printf("Please enter the first letter of your name:");
scanf("%c",&letter);

//same way you initialize the grades 
grade1=98
grade2=76
grade3=67.5
grade4=80.5 
//if you initialize the grades then no need to ask the user to Enter the grade 
//and if you want to ask the user to enter the grade then see this codes
int grade1;
int grade2;
float grade3;
float grade4;

printf("Please enter the grade for your first test:");
scanf("%d",&grade1);
//and same for all the grade note grade3 and grade4 is float so you have you use "%f" instead of "%d" in scanf.

基本的C编程错误

3 个答案: