Question

我有以下代码：

// open the database connection
require_once('php/db/connect.php');
// set a log file
$logFile = 'log/php.log';
// set the error and the doCommit to false
$error = false;
$doCommit = false;
// build the query
$query = "SELECT name,gender,email,country FROM tmp_backer WHERE backerid = ?";
// prepare the query
if ($stmt = $mysqli->prepare($query)) {
    // bind the parameters
    $id = $postArray['backerid'];
    $stmt->bind_param('s',  $id);
    // execute the query
    if ($stmt->execute()) {
        // the query is executed!
        $stmt->store_result();
        $tmpArray = array();
        $stmt->store_result();
        $stmt->bind_result( $name,$gender,$email,$country);
        $stmt->fetch();
        // clear the parameters
        $query = '';
        // copy everything to the table 'backer'
        // build the query
        $query = "INSERT INTO backer (backerid,name,gender,email,country) VALUES (?,?,?,?,?)";
        // prepare the query
        if ($stmt = $mysqli->prepare($query)) {
            // bind the parameters
            $stmt->bind_param(
                'ssiss',        
                $id,
                $name,
                $gender,
                $email,
                $country
            );
            if ($stmt->execute()) {
                // the query is executed!
                // set doCommit to true
                $doCommit = true;
            } else {
                // the query could not be executed
                // log this into the log file and send the visitor back to the become a backer page
                error_log(date('Y-m-d H:i:s').' | query could not be executed (INSERT query) '.$stmt->error.PHP_EOL,3,$logFile);
                $error = true;
            };
        } else {
            // the query is invalid
            // log this into the log file and send the visitor back to the become a backer page
            error_log(date('Y-m-d H:i:s').' | query is invalid (INSERT query) '.$stmt->error.PHP_EOL,3,$logFile);
            $error = true;
        };
    } else {
        // the query could not be executed
        // log this into the log file and send the visitor back to the become a backer page
        error_log(date('Y-m-d H:i:s').' | query could not be executed (SELECT query) '.$stmt->error.PHP_EOL,3,$logFile);
        $error = true;
    };
} else {
    // the query is invalid
    // log this into the log file and send the visitor back to the become a backer page
    error_log(date('Y-m-d H:i:s').' | query is invalid (SELECT query) '.$stmt->error.PHP_EOL,3,$logFile);
    $error = true;
};
// check if there where any errors whilst preparing/executing
// the query
if ($error == true) {
    // there were errors
    $mysqli->rollback();
    exit();
} else {
    // there were no errors
    // doCommit was set to true
    if ($doCommit == true) {
        $mysqli->commit();
    };
};
// close the db connection
require_once('php/db/close.php');

第二次查询执行两次，因为我在包含以下文本的日志文件中收到错误：

2015-09-14 21:14:12 |查询无法执行（INSERT查询）重复条目＆＃39; qzdkzkdjzdk＆＃39;关键＆＃39; PRIMARY＆＃39;

backerID是生成的随机密钥，是两个表中的主键（字段：backerid）。查询WORKS，所以数据从表tmp_backer复制到支持者，但问题是页面没有显示（因为第二次执行INSERT查询时，它会遇到错误，所以它会转到它所在的部分喜欢：$mysqli->rollback(); exit();

任何人都可以帮我吗？

Answer 1

删除此行：

if ($doCommit == true) {
    $mysqli->commit();
};

并将其替换为：

$mysqli->commit();

因为if($error == true)已被调用，所以在＆＃34; else＆＃34;之后不会有任何其他事情发生。但如果它是＆＃34;假＆＃34;因为它是＆＃34;假＆＃34; $doCommit必须是＆＃34; true＆＃34;，所以，自动＆＃34;提交它＆＃34;而不是回电话。问题是，你让$doCommit激活了两次。首先，通过常规电话再次当你要求＆＃34;它＆＃34;如果结果是真的。

MySQLI INSERT查询执行两次

1 个答案: