我有一个" Quit"创建Toplevel窗口的按钮,询问用户是否确定要退出。如果"否"单击按钮,窗口被破坏,但是"退出"按钮不再有效。呃," quitter"虚拟事件击键(CTRL-Q,Q和CTRL-C)也停止运行。那是为什么?
from Tkinter import *
class ButtonTestClass(Frame):
def __init__(self):
self.root=Tk()
self.root.title("No Button Tester!")
self.root.option_add('*font', ('arial', 14, 'bold'))
self.frame=Frame(self.root, height=120, width=600, \
borderwidth=2, relief=GROOVE, background='steelblue'
)
self.frame.pack(fill=X, expand=False)
self.frame.pack_propagate(False)
self.label = Label(self.frame, \
text='Why does the "Quit" button stop working\nafter the "No" button is clicked?', bg='steelblue')
self.label.pack(padx=25, pady=15, side=TOP)
self.root.event_add('<<ev_quit>>', '<Control-c>', '<Control-q>', '<q>')
self.root.bind('<<ev_quit>>', lambda e: self.bye_bye())
self.byeWindow = None
print "In constructor self.byeWindow - value: '%r' type: '%r'" % (self.byeWindow, type(self.byeWindow)) # <<< DEBUG >>>
def createQuitButton(self):
pbx=250; pby=70; pbw=75; pbh=25; pbp=10
self.quitBtn=Button(self.frame, text='Quit', activebackground='steelblue3', font='arial 10 bold', bg='steelblue', command=lambda: self.bye_bye())
self.quitBtn.place(x=pbx, y=pby, width=pbw, height=pbh)
pbx += pbw + pbp
def dontQuit(self, tlref):
self.byeWindow = None # <<<--- There was a 'misspelling' here; grrrr!
tlref.destroy()
print "In dontQuit(). self.byeWindow - value: '%r' type: '%r'" % (self.byeWindow, type(self.byeWindow)) # <<< DEBUG >>>
def bye_bye(self):
if self.byeWindow is not None:
return
self.byeWindow=Toplevel()
print "In bye_bye(), self.byeWindow - value: '%r' type: '%r'" % (self.byeWindow, type(self.byeWindow)) # <<< DEBUG >>>
self.byeWindow.title("Really quit?")
self.byeWindow.config(bg='steelblue', height=40, width=80)
sureMsgLabel=Label(self.byeWindow, text="Are you sure you want to quit?", font='arial 11 bold', bg='steelblue')
sureMsgLabel.pack(side=TOP, padx=10, pady=15)
yesButton=Button(self.byeWindow, text=" Yes. ", font='arial 10 bold', bg='steelblue', activebackground='steelblue3', command=lambda: quit())
yesButton.pack(side=LEFT, anchor=N, padx=40, pady=20)
yesButton.bind('<Key-Return>', lambda: yesButton.invoke())
noButton = Button(self.byeWindow, text=" No. ", activebackground='steelblue3', font='arial 10 bold', bg='steelblue', command=lambda: self.dontQuit(self.byeWindow))
noButton.focus_force()
noButton.pack(side=RIGHT, anchor=N, padx=40, pady=20)
noButton.bind('<Key-Return>', lambda: noButton.invoke())
bT = ButtonTestClass()
bT.createQuitButton()
if __name__ == '__main__':
bT.root.mainloop()
P.S。如果您运行此代码段,您将看到我的意思,以防我没有清楚地描述该问题。 Ta ...
答案 0 :(得分:0)
事实证明,在最后的分析中,我的问题是一个实例变量的拼写错误:“byWindow”而不是“byeWindow”,它在我的self.bye_bye()函数中包含了if语句。纠正拼写修复了问题。非常感谢和亲切的问候Bryan Oakley的深刻见解和圣人建议。这是完美运行的程序......
from Tkinter import *
class ButtonTestClass(Frame):
def __init__(self):
self.root=Tk()
self.root.title("Button Tester!")
self.root.option_add('*font', ('arial', 14, 'bold'))
self.frame=Frame(self.root, height=120, width=600, \
borderwidth=2, relief=GROOVE, background='steelblue'
)
self.frame.pack(fill=X, expand=False)
self.frame.pack_propagate(False)
self.label = Label(self.frame, \
text='Wanna see a "Quit" button working flawlessly?', bg='steelblue')
self.label.pack(padx=25, pady=15, side=TOP)
self.root.event_add('<<ev_quit>>', '<Control-c>', '<Control-q>', '<q>')
self.root.bind('<<ev_quit>>', lambda e: self.bye_bye())
self.byeWindow = None
def createQuitButton(self):
pbx=250
pby=70
pbw=75
pbh=25
pbp=10
self.quitBtn=Button(
self.frame,
text='Quit',
activebackground='steelblue3',
font='arial 10 bold',
bg='steelblue',
command=self.bye_bye
)
self.quitBtn.place(
x=pbx,
y=pby,
width=pbw,
height=pbh
)
pbx += pbw + pbp
def dontQuit(self, tlref):
tlref.destroy()
self.byeWindow = None
def bye_bye(self):
if self.byeWindow is not None:
return
self.byeWindow=Toplevel()
self.byeWindow.title("Really quit?")
self.byeWindow.config(bg='steelblue', height=40, width=80)
sureMsgLabel=Label(self.byeWindow,
text="Are you sure you want to quit?",
font='arial 11 bold',
bg='steelblue'
)
sureMsgLabel.pack(side=TOP, padx=10, pady=15)
yesButton=Button(self.byeWindow,
text=" Yes. ",
font='arial 10 bold',
bg='steelblue',
activebackground='steelblue3',
command=lambda: quit()
)
yesButton.pack(side=LEFT, anchor=N, padx=40, pady=20)
yesButton.bind('<Key-Return>', lambda: yesButton.invoke())
noButton = Button(self.byeWindow,
text=" No. ",
activebackground='steelblue3',
font='arial 10 bold',
bg='steelblue',
command=lambda: self.dontQuit(self.byeWindow)
)
noButton.focus_force()
noButton.pack(side=RIGHT, anchor=N, padx=40, pady=20)
noButton.bind('<Key-Return>', lambda: noButton.invoke())
bT = ButtonTestClass()
bT.createQuitButton()
if __name__ == '__main__':
bT.root.mainloop()
嗯,这本身并不是一个真正的程序,而是从一个程序中提取的一些“按钮无效”问题。干杯!