Why can't I pass dependencies task when I bundle tasks in Gulp

Question

If I execute this code it will throw an error saying it only accepts a function instead of the three tasks

gulp.task('build', ['clean'], ['styles', 'scripts', 'images']);

I want to execute the clean task before the other three, I don't want to wire the clean task to each single task when I define them as clean will delete my whole build folder.

How do I do it?

This is the API reference https://github.com/gulpjs/gulp/blob/master/docs/API.md#gulptaskname-deps-fn

Answer 1

使用

gulp.task（'build'，['clean'，'styles'，'scripts'，'images']）;

清理任务将是构建依赖于启动的第一个任务，但它们将全部并行启动。首先启动清洁是由于实施，可能会更改，恕不另行通知。

这应该有效：

gulp.task('build', ['clean'], function(cb)
{
var runSequence = require('run-sequence');
  runSequence( ['styles', 'scripts', 'images']);
} );