BETWEEN运算符mySQL PHP

时间:2015-09-14 15:06:01

标签: php mysql date between

所有

不确定为什么我在运行以下查询时收到错误:

SELECT COUNT(R.id) AS total 
                    FROM request as R 
                    INNER JOIN users AS U ON U.uin = R.engineer_uin 
                    WHERE U.gm = 'BVG1'
                    AND R.date_received BETWEEN DATE_FORMAT(R.date_received,'%d %m %Y')='01 04 2014' AND DATE_FORMAT(NOW(),'%d %m %Y')

R.date_received采用以下格式:2015-06-01 14:38:46 我只想在Now()和前一年之间得到结果。 (在英国,我们的财政年度是从4月到明年4月。

错误是:

#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '='01 04 2014' AND DATE_FORMAT(NOW(),'%d %m %Y')
LIMIT 0, 25' at line 5 

有什么想法吗?

1 个答案:

答案 0 :(得分:2)

The AND clause you're looking for should look as follows:

...
AND R.date_received BETWEEN STR_TO_DATE('01,04,2014','%d,%m,%Y') AND NOW()