Question

我的SQLiteOpenHelper类：

public class MyUsersDatabaseAdapter
{
    MyUsersDatabase myUsersDatabase;
    SQLiteDatabase sqLiteDatabase;

public MyUsersDatabaseAdapter(Context context, String name, CursorFactory factory,int version)
{
    myUsersDatabase = new MyUsersDatabase(context, name, factory, version);
}

public long inserDataToDatabase(String firstName,String lastName)
{
    sqLiteDatabase = myUsersDatabase.getWritableDatabase(); // sqliteDatabase is a reference to my database

    ContentValues contentValues = new ContentValues();
    contentValues.put(MyUsersDatabase.FIRST_NAME,firstName ); // First parameter(key) is the name of the column
    contentValues.put(MyUsersDatabase.LAST_NAME, lastName);

    long id = sqLiteDatabase.insert(MyUsersDatabase.TABLE_NAME, null, contentValues);
    return id;
}

static class MyUsersDatabase extends SQLiteOpenHelper
{
    private static final int DATABASE_VERSION = 4;
    private static final String DATABASE_NAME = "usersDatabase";
    private static final String TABLE_NAME = "usersTable";
    private static final String UID = "_id"; // User identification number
    private static final String FIRST_NAME = "First Name"; // Column
    private static final String LAST_NAME = "Last Name"; // Column
    private static final String CREATE_TABLE = "CREATE TABLE " + MyUsersDatabase.DATABASE_NAME + "(" 
    + UID + " INTEGER PRIMARY KEY AUTOINCREMENT, " 
    + FIRST_NAME + " TEXT, " 
    + LAST_NAME + " TEXT);";
    private static final String DROP_TABLE = "DROP TBALE IF EXIST " + TABLE_NAME;

    private Context context;


    public MyUsersDatabase(Context context, String name, CursorFactory factory,int version)
    {
        super(context, DATABASE_NAME, null, DATABASE_VERSION);

        this.context = context;
        ToastMessage.message(context, "Constructor was called");
    }

    @Override
    public void onCreate(SQLiteDatabase db) 
    {
        ToastMessage.message(context, "onCreate() was called");
        try
        {
            db.execSQL(CREATE_TABLE);
        }
        catch (SQLException e)
        {
            ToastMessage.message(context,"" + e);
        }
    }
    @Override
    public void onUpgrade(SQLiteDatabase db, int oldVersion, int newVersion) 
    {
        ToastMessage.message(context, "onUpgrade() was called");
        try
        {
            db.execSQL(DROP_TABLE);
            onCreate(db);
        } 
        catch (SQLException e) 
        {
            ToastMessage.message(context,"" + e);
        }
    }
}

logcat的：

09-14 16:50:13.711: E/SQLiteLog(26257): (1) near "Name": syntax error
09-14 16:50:13.713: E/SQLiteDatabase(26257): Error inserting Last Name= First Name=
09-14 16:50:13.713: E/SQLiteDatabase(26257): android.database.sqlite.SQLiteException: near "Name": syntax error (code 1): , while compiling: INSERT INTO usersTable(Last Name,First Name) VALUES (?,?)
09-14 16:50:13.713: E/SQLiteDatabase(26257):    at android.database.sqlite.SQLiteConnection.acquirePreparedStatement(SQLiteConnection.java:894)
09-14 16:50:13.713: E/SQLiteDatabase(26257):    at android.database.sqlite.SQLiteConnection.prepare(SQLiteConnection.java:505)
09-14 16:50:13.713: E/SQLiteDatabase(26257):    at android.database.sqlite.SQLiteProgram.<init>(SQLiteProgram.java:58)
09-14 16:50:13.713: E/SQLiteDatabase(26257):    at android.database.sqlite.SQLiteDatabase.insertWithOnConflict(SQLiteDatabase.java:1570)

点击LogCat后，我就抓住了这个Button。

主要课程：

protected void onCreate(Bundle savedInstanceState) 
{
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_sign_up);

    viewsInitialization();

    getWindow().setSoftInputMode(WindowManager.LayoutParams.SOFT_INPUT_STATE_ALWAYS_HIDDEN);

    myUsersDatabase = new MyUsersDatabaseAdapter(SignUpActivity.this,"UsersDatabase" , null, 1);
contentValues = new ContentValues();

    signUpButton.setOnClickListener(new View.OnClickListener()
    {   
        @Override
        public void onClick(View v) 
        {
            userFirstName = firstNameEditText.getText().toString();
            userLastName = lastNameEditText.getText().toString();

            id = myUsersDatabase.inserDataToDatabase(userFirstName, userLastName);
            if (id < 0)
            {
                ToastMessage.message(SignUpActivity.this, "Unsuccessful row insertion");
            }
            else 
            {
                ToastMessage.message(SignUpActivity.this, "Successful row insertion");
            }
        }
    });
}

还有Toast“不成功的行插入”。

我的代码怎么了？

修改

从列名中删除空格后，我得到了这个LogCat：

9-14 17:17:04.049: E/SQLiteLog(32247): (1) table usersTable has no column named LastName
09-14 17:17:04.051: E/SQLiteDatabase(32247): Error inserting LastName=hsh FirstName=hshsh
09-14 17:17:04.051: E/SQLiteDatabase(32247): android.database.sqlite.SQLiteException: table usersTable has no column named LastName (code 1): , while compiling: INSERT INTO usersTable(LastName,FirstName) VALUES (?,?)
09-14 17:17:04.051: E/SQLiteDatabase(32247):    at android.database.sqlite.SQLiteConnection.nativePrepareStatement(Native Method)
09-14 17:17:04.051: E/SQLiteDatabase(32247):    at android.database.sqlite.SQLiteConnection.acquirePreparedStatement(SQLiteConnection.java:894)

Answer 1

您不应在表名中使用空格。如果您这样做，则必须在名称周围使用反引号。更好的解决方案是重命名列而不使用空格。

Answer 2

问题是您的表中包含空格的列，并且列名不包含在刻度字符（`）中。您可以通过以下两种方式解决此问题：

第一种方式（推荐）

从＆＃34;名字＆＃34;重命名您的表格列和＆＃34;姓氏＆＃34;到＆＃34; FirstName＆＃34;和＆＃34;姓氏＆＃34; （注意删除的空间）。执行此操作后，您将需要触发对onUpgrade的调用，以便运行升级代码（在您的情况下，它将删除旧表，以便可以创建新表）。之后，您的列名将匹配，没有空白字符，您的数据库应该运行良好。

进行此更改后，您的旧数据库仍将处于完好状态，需要使用新列进行更新。您可以删除旧列，也可以使用上一段中提到的onUpgrade SQLiteOpenHelper功能。

第二种方式 （不太好）但包括完整性

在代码周围添加标记：

private static final String CREATE_TABLE = "CREATE TABLE " + MyUsersDatabase.DATABASE_NAME + "(" 
+ UID + " INTEGER PRIMARY KEY AUTOINCREMENT, " 
+ "`" + FIRST_NAME + "` TEXT, " 
+ "`" + LAST_NAME + "` TEXT);";

这样可行，但在列名中包含空格字符通常被认为是不好的做法。

最后的想法

您可以在列名称周围添加刻度，因为刻度只是定义包含在内的内容是单个对象，并且应该一起解析。此外，其中包含空格的列名是不好的做法，您不应该在表名中包含空格（即使可能）。

SQLiteException：接近“”语法错误

2 个答案: