Question

例如，我想打开一个会话和一个通道，然后执行严格的不同命令。我有InitializeSSHSession和Initialize SSH通道方法可以在下面看到。

 void Computer::InitializeSSHSession()
 {
 ssh_session remoteSSHSession = ssh_new();

if ( remoteSSHSession )
{
    QString password = this->GetPassword();
    QString remoteIP = this->GetIP();
    QString userName = this->GetUserNameW();

    ssh_options_set(remoteSSHSession, SSH_OPTIONS_HOST, remoteIP.toStdString().c_str());
    ssh_options_set(remoteSSHSession, SSH_OPTIONS_LOG_VERBOSITY, &sessionVerbosity);
    ssh_options_set(remoteSSHSession, SSH_OPTIONS_PORT, &sessionPort);
    ssh_options_set(remoteSSHSession, SSH_OPTIONS_USER, userName.toStdString().c_str());

    int remoteConnection = ssh_connect(remoteSSHSession);
    if ( remoteConnection == SSH_OK )
    {
        int authenticateControl = ssh_userauth_password(remoteSSHSession, NULL, password.toStdString().c_str());
        if ( authenticateControl == SSH_AUTH_SUCCESS )
        {
            InitializeSSHChannel(remoteSSHSession);
        }
        else
        {
            remoteSSHSession = NULL;
        }
    }
    else
    {
        remoteSSHSession = NULL;
    }
}
else
{
     remoteSSHChannel = NULL;
}
}

void Computer::InitializeSSHChannel(ssh_session remoteSSHSession)
{
remoteSSHChannel = ssh_channel_new(remoteSSHSession);

if ( remoteSSHChannel )
{
    int channelControl = ssh_channel_open_session(remoteSSHChannel);
    if ( channelControl != SSH_OK )
    {
        EventLogger::LogMessage(true, "SSH channel sesssion failed!");
        ssh_channel_free(remoteSSHChannel);
    }
}
 }

总的来说，我正在初始化会话并获得这样的频道：

 InitializeSSHSession();
 ssh_channel channel = GetSSHChannel();

然后

  int rc = ssh_channel_request_exec(channel, "ls -l");

它可以正确执行但是当我想执行另一个命令它不执行时，我应该返回进程的开始首先初始化会话并再次获取通道。

对于每个命令都不是好的解决方案。一旦初始化会话而不是一次又一次地为每个命令使用它，是否可以这样做？

如何在libssh中打开一个通道而不是执行几个不同的命令？

0 个答案: