Question

我正在尝试使用swift获取请求并填充我的i<=N。截至目前，我已准备好table view数据，需要在我的json中填写

由于我刚开始学习swift，我发现提出请求有点令人困惑。这是我的table

RestaurantTableViewController.swift

这是我迄今为止所做的一切，在此之后，我应该如何让override func viewDidLoad() { super.viewDidLoad() var url: String = "http://localhost:8888/restaurant/registeruser.php" var request: NSMutableURLRequest = NSMutableURLRequest() request.URL = NSURL(string: url) request.HTTPMethod = "GET" request.timeoutInterval = 60 NSURLConnection.sendAsynchronousRequest(request, queue: NSOperationQueue()) { (respose:NSURLResponse!, data:NSData!, error:NSError!) -> Void in var error: AutoreleasingUnsafeMutablePointer<NSError?> = nil let jsonResult: NSDictionary! = NSJSONSerialization.JSONObjectWithData(data, options: NSJSONReadingOptions.MutableContainers, error: error) as? NSDictionary if (jsonResult != nil){ //success println(jsonResult) let dataArray = jsonResult["name"] as! NSArray; for item in dataArray { //loop through data items let obj = item as! NSDictionary for(key, value) in obj{ let allnames = obj["name"] as! NSString; } } } } }充满table，restaurant name和type。任何彻底的帮助将不胜感激。

Answer 1

我建议使用https://github.com/daltoniam/JSONJoy-Swift它会使事情变得更容易和更清洁。

至于电话

var DISPATCH_TIME_FOREVER: UInt64 { get }

var url: String = "http://localhost:8888/restaurant/registeruser.php"
let sem = dispatch_semaphore_create(0)

var responseData = NSData()
NSURLSession.sharedSession().dataTaskWithURL(url, completionHandler: {(data, response, error) -> Void in
        responseData = data
        dispatch_semaphore_signal(sem)
    }).resume()
    dispatch_semaphore_wait(sem, DISPATCH_TIME_FOREVER)
    let jsonResult: NSDictionary! = NSJSONSerialization.JSONObjectWithData(responseData, options: NSJSONReadingOptions.MutableContainers, error: error) as? NSDictionary

        if (jsonResult != nil){
            //success
            println(jsonResult)

            let dataArray = jsonResult["name"] as! NSArray;

            for item in dataArray {  //loop through data items

                let obj = item as! NSDictionary

                for(key, value) in obj{

                    let allnames = obj["name"] as! NSString;
                }
            }
        }

Answer 2

最好的代码如下我每次做请求都用它希望对你有帮助！

   let url = URL(string: "https://google.com")
    let task = URLSession.shared.dataTask(with: ((url ?? URL(string: "https://google.com"))!)) { [self] (data, response, error) in
        
        do {
            let jsonResponse = try JSONSerialization.jsonObject(with: data!, options: [])
            print(jsonResponse)
            guard let newValue = jsonResponse as? [String:Any] else {
                print("invalid format")
                }
            }

        
        catch let error {
            print("Error: \(error)")
        }
        
    task.resume()
}

使用swift进行HTTP GET请求

2 个答案: