Question

如果我在更新方法中实现了该方法，我想在几秒内计算它只在第一秒工作，然后它不停地打印数字而不等待一秒钟，然后打印下一个数字; 我不明白为什么会发生这种情况

 -(void) countinSeconds{
            SKAction *count = [SKAction waitForDuration:1];

            SKAction *time = [SKAction runBlock:^{
                    timex++;
                       }];
            SKAction *print = [SKAction runBlock:^{
            NSLog(@"%i",timex);
            }];
            [self runAction:[SKAction sequence:@[count,time,print]]];



        }
        -(void)update:(NSTimeInterval)currentTime {

                    [self countinSeconds];

        }

Answer 1

没有必要为此采取行动; update:方法是在当前时间传递的，所以只需要记住你何时开始并做一些简单的数学运算：

@implementation YourClass () {
    BOOL _started;
    NSTimeInterval _startTime;
    NSUInteger _lastLogTime;
}
@end

@implementation YourClass

- (void)update:(NSTimeInterval)currentTime
{
    if (!_started) {
        _startTime = currentTime;
        _started = YES;
    } else {
        NSUInteger elapsedTime = (NSUInteger)(currentTime - _startTime);
        if (elapsedTime != _lastLogTime) {
            NSLog(@"Tick: %lu", elapsedTime);
            _lastLogTime = elapsedTime;
        }
    }
}

@end

Answer 2

以下是SKAction如何做到这一点：

您不想在update：中运行该方法，而是在其他地方运行，例如在didMoveToView中运行：

-(void)didMoveToView:(SKView *)view {
   [self countinSeconds];
}

此外，你不需要两个街区：

-(void) countinSeconds{


    SKAction *wait = [SKAction waitForDuration:1];

    SKAction *print = [SKAction runBlock:^{
        timex++;
         NSLog(@"%i",timex);
    }];


     [self runAction:[SKAction repeatActionForever:[SKAction sequence:@[wait,print]]] withKey:@"counting"];



}

要停止计时器，您可以随时删除与＆＃34;计数＆＃34;相关联的操作。关键，像这样：

if([self actionForKey: @"counting"){[self removeActionForKey:@"counting"];}

SpriteKit中的更新方法不能正确更新时间

2 个答案: