如何在C

Question

我想将一系列整数转换为十进制。我知道程序但是如何将所有整数作为一个二进制数？

输出必须如下：

Enter first binary digit: 0
Enter second binary digit: 0
Enter third binary digit: 0
Enter fourth binary digit: 0
0000 = 0

以下是我编写此任务的方法：

#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#include<conio.h>

int main(void)
    {
        int a[100];
        int n, dec = 0; int power(int, int);

        long int binaryNumber, decimalNumber = 0, j = 1, remainder;  

        printf("Enter first binary number: ");
        scanf("%ld", &a[1]);
        printf("Enter second binary number: ");
        scanf("%ld", &a[2]);
        printf("Enter third binary number: ");
        scanf("%ld", &a[3]);
        printf("Enter fourth binary number: ");
        scanf("%ld", &a[4]);

        for (int i = 0;i<n;i++)
        {
            scanf("%d", &a[i]);
        }

        for (int i = (n - 1);i >= 0;i--)
        {
            dec = (a[i] * power(2, j)) + dec;
            j++;
        }
        printf("binary number of decimal is %d", dec);

        return 0;
    }

Answer 1

嗯，这是简单的数学。第一个二进制数字是2​​ ^ 0，第二个2 ^ 1，第三个2 ^ 2，...

number = first * 1 + second * 2 + third * 4 + forth * 8;

Answer 2

//binary to decimal converter
long int bin2dec(long int binary_number,int i){
 if(binary_number == 0)
    return 0;
 else
    return ((binary_number%10)*pow(2,i) + bin2dec(binary_number/10,++i));
}