Question

我想找几年，几周和几年。 C中的日子。我不知道我的代码有什么问题。请帮忙：

#define _CRT_SECURE_NO_WARNINGS
#include <stdio.h>

#define DAYS_PER_WEEK 7
#define WEEKS_PER_YEAR 52
#define DAYS_PER_YEAR 364

int main(void)
{

    int a;  int y; double w; double days; int weeks;

    printf("Enter the time in days: ");
    scanf("%d", &a);


    y = a / DAYS_PER_YEAR;
    w = ((a/ DAYS_PER_YEAR) - y)* WEEKS_PER_YEAR;
    weeks = ((a / DAYS_PER_YEAR) - y)* WEEKS_PER_YEAR;
    days = (w - weeks)* DAYS_PER_WEEK;

    printf(" %d days is %d years, %d weeks and %d days", a, y, weeks, days);


    return 0;
}

谁能告诉我哪里出错了？我怀疑问题出在printf函数。

Answer 1

首先，DAYS_PER_YEAR应该是365（没有餐饮闰年）。

其次，使用运算符'%'来简化计算：

#include <stdio.h>

#define DAYS_PER_WEEK  7
#define WEEKS_PER_YEAR 52
#define DAYS_PER_YEAR  365

int main(void)
{
    int a, years, weeks, days, remains;

    printf("Enter the time in days: ");
    scanf("%d", &a);

    years = a / DAYS_PER_YEAR;
    remains = a % DAYS_PER_YEAR;
    weeks = remains / DAYS_PER_WEEK;
    days = remains % DAYS_PER_WEEK;

    printf("%d days is %d years, %d weeks and %d days\n", a, years, weeks, days);

    return 0;
}

用C计算时间

1 个答案: