Question

我有一个结构为：

的JSON文件

Arrow

我想把它转换成结构的字典（或任何有用的东西）：

import javax.swing.JApplet;
import java.util.*;
import java.awt.*;

public class Shapes extends JApplet
{
    public void paint (Graphics page)
    {
        resize(400,300);
        Random rand = new Random();

        // Declare size constants
        final int circleMax = 160,circleMin = 40; // circle max and min diameter
        final int locMaxX = 360, locMaxY = 260;
        int radiusSize = 0, locationx = 0,locationy = 0 ;

        // Declare variables
        radiusSize = (rand.nextInt(circleMax)+ circleMin); 
        locationx =20 ;//rand.nextInt(locMaxX)+ 20;
        locationy =20 ;// rand.nextInt(locMaxY) + 20;

        // Draw the circle 1
        page.drawOval(locationx, locationy, radiusSize,radiusSize);
    }
}

我正在尝试以下方法：

[ {"unit_id": {"type":[string],"customer_id":[int]} },

...,

...]

哪个失败，因为该文件无法反序列化为该结构。我也尝试过创建一个类：

Dictionary<int,Tuple<string,int>>

然后：

Dictionary<int, Tuple<string,int>> units =
JsonConvert.DeserializeObject<Dictionary<int, Tuple<string, int>>>
(File.ReadAllText(jsonFile));

哪个没有失败，但没有用任何值填充列表。

由于

Answer 1

对于您的JSON结构，您可能需要创建如下类：

    class Unit
    {
        public CustomerType UnitId;
    }

    class CustomerType
    {
        public int CustomId { get; set; }
        public string Type { get; set; }
    }

或使用dynamic：

        Unit unit = new Unit();
        unit.UnitId = new CustomerType()
        {
            CustomId = 1001,
            Type = "Customer"
        };

        //generate test json string
        string jsonTest = JsonConvert.SerializeObject(unit);

        //convert to dynamic
        var result = JsonConvert.DeserializeObject<dynamic>(jsonTest);
        Console.WriteLine(result.UnitId.CustomId);
        Console.WriteLine(result.UnitId.Type);

Answer 2

所以我设法使用以下（杂乱的）代码创建我的字典：

public static Dictionary<int, Tuple<string, int>> parseJsonIntoDictionary(string jsonFile) {
    Dictionary<int, Tuple<string, int>> unitDictionary = new Dictionary<int,Tuple<string,int>>();
    var json = System.IO.File.ReadAllText(jsonFile);
    var units = JArray.Parse(json);
    foreach (JToken unit in units) {
        JProperty property = ((JObject)unit).Properties().ToArray()[0];
        int unitID = Convert.ToInt32(property.Name);
        Tuple<string,int> tempTuple = new Tuple<string,int>(Convert.ToString(unit[property.Name]["unit_type"]),Convert.ToInt32(unit[property.Name]["customer_id"]));
        unitDictionary[unitID] = tempTuple;
    }
    return unitDictionary;
}

C＃将JSON反序列化为Dictionary <int，tuple <string，int>＆gt;

2 个答案: