Question

我的画廊存在问题。我的网址是数字我需要改为混合数字和单词。我在$fid = $_GET['name'];之前更改了$_GET['id']，现在图像没有显示。怎么办？

Mysql表：

CREATE TABLE IF NOT EXISTS `gallery` (
`id` int(12) NOT NULL,
  `link` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
  `title` varchar(255) COLLATE utf8_unicode_ci NOT NULL,
  `des` text COLLATE utf8_unicode_ci NOT NULL,
  `fid` int(12) NOT NULL
) ENGINE=InnoDB AUTO_INCREMENT=16 DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;

PHP代码：

<?php
    $fid = mysql_real_escape_string($_GET["name"]);
    $book= mysql_query("SELECT * from books WHERE id='$fid'") or die(mysql_error());
    if(mysql_num_rows($books) != 0) { 
    $row = mysql_fetch_array($books); 
?>

<?php 
$fid = $_GET['name'];
$gallery = mysql_query("SELECT * FROM gallery WHERE id='$fid'") or die (mysql_error());
    while($gal = mysql_fetch_array($gallery)){
    $linkgal = $gal['link'];
    $title = $gal['title'];
    $id = $gal['id'];
    $fid = $gal['fid'];

    echo "'<img src='/uploads/gallery/$linkgal' title='$title' alt='$title' style='height:180px; margin-left:23px;cursor: pointer;'";

    echo 'onclick="PopupCenter';
    echo "('/photos.php?fid=$fid&id=$id', 'xtf', '990', '670')";
    echo '"/>';
    }   
    ?>

Answer 1

好的我已经完成了。我已经添加了数组和$ _GET.Now它的工作原理。实际上它是打开另一个窗口，图像在那里。如何使用像这样的jquery：http://www.1stwebdesigner.com/wp-content/uploads/2010/01/jquery-gallery-solutions/galleria-jquery-image-slideshow-tools-free.jpg

  <?php 

    >       $id = $_GET['name'];
    >       $book = mysql_query("SELECT * FROM `books` WHERE `name`='$id'") or die (mysql_error());
    >       $books = mysql_fetch_array($book);
    >       $id = $book['id'];
    >       $name = $book['name'];




        $gallery = mysql_query("SELECT * FROM `gallery` WHERE `fid`='$id' ORDER BY `id`") or die (mysql_error());
            while($gal = mysql_fetch_array($gallery)){
            $linkgal = $gallink'];
            $title = $gal['title'];
            $id = $gal['id'];
            $fid = $gal['fid'];

            echo "'<img src='/uploads/gallery/$linkgal' title='$title' alt='$title' style='height:180px; margin-left:23px;cursor: pointer;'";

            echo 'onclick="PopupCenter';
            echo "('/photos.php?fid=$fid&id=$id', 'xtf', '990', '670')";
            echo '"/>';
            }   
            echo '</div>';
            ?>

PHP / Mysql图库代码更改删除图像，如何解决？

1 个答案: