用制表符替换空格缩进(PCRE)

时间:2015-09-13 11:11:13

标签: regex pcre

我想展示一下我可以用制表符替换空格缩进,但只显示每行的前导空格。

我想我可以通过可变宽度的后视来实现这一点。不幸的是,PCRE不允许这样做。

s/(?<=^|(?:[ ]{3})+)[ ]{3}(?=\S|(?:[ ]{3})+\S)/\t/g

还有其他办法吗?

当然,一般的想法是不要通过重复替换来做循环。这太容易了......

以下是随机输入的示例,其中必须将2个空格转换为制表符:

  if (c == 1&d == 2){
    for (uinc = 1;uinc< = p1;uinc++){  // for fixed u calculate various w's
      if (1.0-u<5e-6)u = 1.0; // fix up the u = 1 value because of float
      w = 0.0;
      for (winc = 1;winc< = p2;winc++){
        if (1.0-w<5e-6)w = 1.0; // fix up the w = 1 value because of float
        for (i = 0;i< = n;i++){
          jin = Basis(n,i,u); // Bernstein basis function in the u direction (see Eq.(5.2))
          if (jin! = 0.){ // don't bother no contribution
            jbas = 3*(m+1)*i; /* column index for lineal array*/
            for (j = 0;j< = m;j++){
              kjm = Basis(m,j,w);  // Bernstein basis function in the w direction (see Eq.(5.2))
              if (kjm! = 0.){ // don't bother no contribution
                j1 = jbas+3*j+1;
                q[icount] = q[icount]+b[j1]*jin*kjm; // calculate the surface points
                q[icount+1] = q[icount+1]+b[j1+1]*jin*kjm;
                q[icount+2] = q[icount+2]+b[j1+2]*jin*kjm;
              }
            }
          }
        }
        icount += 3;
        w = w+stepw;
      }
      u += stepu;
    }
  }
}

0 个答案:

没有答案