我想创建一个当前显示我的应用程序的位图,我进入的一件事是无法读取FB缓冲区需要root,想知道是否有可能为屏幕创建图像文件,请我希望帮助对此进行编码,没有第三方意图,谢谢,答案将不胜感激
答案 0 :(得分:0)
来自您的活动(伪代码):
Bitmap bm = Bitmap.create...
Canvas canvas = new Canvas(bm);
getWindow.getDecorView().draw(canvas);
答案 1 :(得分:0)
您可以使用FFMPEG捕获屏幕
答案 2 :(得分:0)
试试这个......
{
LinearLayout view = (LinearLayout) findViewById(R.id.imageLayout);
View v1 = view.getRootView();
v1.setDrawingCacheEnabled(true);
String dir="myimages";
Bitmap bm = v1.getDrawingCache();
saveBitmap(bm, dir, "capturedimage");
}
static String saveBitmap(Bitmap bitmap, String dir, String baseName) {
try {
File sdcard = Environment.getExternalStorageDirectory();
File pictureDir = new File(sdcard, dir);
pictureDir.mkdirs();
File f = null;
for (int i = 1; i < 200; ++i) {
String name = baseName + i + ".png";
f = new File(pictureDir, name);
if (!f.exists()) {
break;
}
}
System.out.println("Image size : "+bitmap.getHeight());
if (!f.exists()) {
String name = f.getAbsolutePath();
FileOutputStream fos = new FileOutputStream(name);
bitmap.compress(Bitmap.CompressFormat.PNG, 100, fos);
System.out.println("After File Size : "+f.length());
fos.flush();
fos.close();
return name;
}
} catch (Exception e) {
e.printStackTrace();
System.out.println("Exception in saveBitmap: "+e.getMessage());
} finally {
}
return null;
}