Question

我需要编写一个代码，在屏幕上放置一张图片，一旦点击图片就播放声音，然后点击之后点击的任何地方都会放置贴纸。我完成了图片和声音部分，但我很难贴上贴纸。我目前正在尝试编写命令if (EZInteraction.wasMouseLeftButtonReleased() && hatsound.play()) {。但它不会起作用，如果我添加括号并将代码更改为if (EZInteraction.wasMouseLeftButtonReleased()) && (hatsound.play()) {，它将在令牌＆amp;＆amp;和invalid OnlySynchronized无效。请帮忙。这是我第一个参加CS的学期。我的声音和贴纸部分的代码是

while(true) { //while loop is always true
    int clickX = EZInteraction.getXMouse(); // declare an integer variable called clickX and the X mouse coordinate integer is assigned to it
    int clickY = EZInteraction.getYMouse(); // declare an integer variable called clickY and assign to it the Y mouse coordinate integer

    if (EZInteraction.wasMouseLeftButtonReleased()){  //if the left mouse button is released then
        if (hatPicture.isPointInElement(clickX, clickY)){ //if the left mouse button is release on this picture
            hatsound.play(); //then hatsound will play
        }
        if (EZInteraction.wasMouseLeftButtonReleased()) && (hatsound.play()) { //if left mouse released and hat sound plays then
            EZ.addImage("hat.png", clickX, clickY); //hat.png will be placed
        }

Answer 1

你试图找出声音是否必须播放？我认为hatsound.play()不会返回boolean。你可以通过以下方式引入一个布尔变量来做到这一点。

int clickNum = 0;
boolean hatSoundPlay = false;
while(true) { //while loop is always true
    int clickX = EZInteraction.getXMouse(); // declare an integer variable called clickX and the X mouse coordinate integer is assigned to it
    int clickY = EZInteraction.getYMouse(); // declare an integer variable called clickY and assign to it the Y mouse coordinate integer

    if (EZInteraction.wasMouseLeftButtonReleased()){  //if the left mouse button is released then
        if (hatPicture.isPointInElement(clickX, clickY)){ //if the left mouse button is release on this picture
            if (!hatSoundPlay) {
                hatsound.play(); //then hatsound will play
                hatSoundPlay = true;
            } else {
                EZ.addImage("hat.png", clickX, clickY); //hat.png will be placed
                hatSoundPlay = false;
            }
        }
    } 
}

最好的方法是看到播放声音的类的引用，并找出方法和变量是什么。您的hatsound变量的类型是什么？

代码为＆＃34;如果鼠标在图片上发布，请选择图片。鼠标再次释放，然后放置图片＆＃34;

1 个答案: