Question

所以我试图创建一个简单的计算器，我认为这个代码没有任何问题但是当我运行代码时，它说有语法错误：解析时意外的EOF（[字符串]，第1行）我尝试了几个更改，但我仍然无法看到错误，请帮帮我？

operation = input ("Pick your operation:  +  |  -  |  *  |  /   ")

    if operation == '+' :
        no1 = int(input ("Pick a number"))
        no2 = int(input ("Pick another number"))
        answer = no1 + no2
        print ( "Answer:", no1 , "+" , no2 , "=", answer)

    elif operation == '-':
        no1 = int(input ("Pick a number"))
        no2 = int(input ("Pick another number"))
        answer = no1 - no2
        print ( "Answer:", no1 , "-" , no2 , "=" , answer)

    elif operation == '*':
        no1 = int(input ("Pick a number"))
        no2 = int(input ("Pick another number"))
        answer = no1 * no2
        print ( "Answer:", no1 , "*" , no2 , "=", answer)

    elif operation == '/':
        no1 = int(input ("Pick a number"))
        no2 = int(input ("Pick another number"))
        answer = no1 / no2
        print ( "Answer:", no1 , "/" , no2 , "=", answer)

    else:
        print ("Please check your given options of operations.")

Answer 1

你的行在Python 2和3中都是有效的，但它只在Python 3中有用。

版本之间的输入行为发生了变化。

在Python 2中，您必须改为使用raw_input：

operation = raw_input("Pick your operation:  +  |  -  |  *  |  /   ")

阅读https://docs.python.org/2.7/library/functions.html#input和https://docs.python.org/3/library/functions.html#input上的文档了解详情。

Answer 2

你需要使用raw_input用于python版本＆lt; 3.0。您可以查看behavior of input

解析时意外的EOF ???

2 个答案: