Question

当我尝试运行这些代码行时，我得到“无法写入未知属性competition_id错误”：

notification = Notification.create(
        user:       subscription.tournament.user,
        content:    "#{subscription.user.full_name} a demandé à s'inscrire à #{subscription.tournament.name} dans la catégorie #{subscription.competition.category} ",
        competition: subscription.competition
      )

我不明白，因为我进行了迁移，将竞争作为通知的外键添加：

    class AddCompetitionToNotification < ActiveRecord::Migration
      def change
        add_reference :notifications, :competition, index: true, foreign_key: true
      end
    end

我的架构也已成功更新，表格通知似乎有外键竞争：

  create_table "notifications", force: :cascade do |t|
    t.integer  "user_id"
    t.string   "content"
    t.datetime "created_at",                     null: false
    t.datetime "updated_at",                     null: false
    t.boolean  "read",           default: false
    t.integer  "convocation_id"
    t.integer  "tournament_id"
    t.integer  "competition_id"
  end

  add_index "notifications", ["competition_id"], name: "index_notifications_on_competition_id", using: :btree
  add_index "notifications", ["user_id"], name: "index_notifications_on_user_id", using: :btree

我的竞争模式有以下关联：

class Competition < ActiveRecord::Base
  belongs_to :tournament

  has_many :subscriptions, dependent: :destroy
  has_many :notifications, dependent: :destroy

我的通知模型

class Notification < ActiveRecord::Base
  belongs_to :user
  belongs_to :convocation
  belongs_to :tournament
  belongs_to :competition
end

这个错误来自哪里？

Answer 1

您可以像这样重新排序函数调用：

notification = subscription.competition.notifications.new |n|
  n.user_id = subscription.tournament.user.id
  n.content = "#{subscription.user.full_name} a demandé à s'inscrire à #{subscription.tournament.name} dans la catégorie #{subscription.competition.category} "
end 
notification.save!

运行成功迁移后出现未知属性错误

1 个答案: