我有一个问题,我不知道如何用ocr中的空格来填充数字。 Ocr用我们的空间获取所有数字..
示例:如果我的图片有数字:65 7 1 22 110 我想要返回65 7 1 22 110 但是ocr返回657122110,没有空格!
这是我的代码:(来自:Simple-Android-OCR)
_path = Environment.getExternalStorageDirectory().toString() + "/DCIM/test.jpg";
Bitmap bm = BitmapFactory.decodeFile(_path);
//ByteArrayOutputStream bos = new ByteArrayOutputStream();
//bm.compress(CompressFormat.JPEG, 75, bos);
TessBaseAPI baseApi = new TessBaseAPI();
baseApi.setPageSegMode(TessBaseAPI.OEM_TESSERACT_CUBE_COMBINED);
baseApi.setPageSegMode(PageSegMode.PSM_AUTO_OSD);
baseApi.setPageSegMode(PageSegMode.PSM_SINGLE_LINE);
baseApi.setPageSegMode(TessBaseAPI.PageSegMode.PSM_OSD_ONLY);
baseApi.setDebug(true);
baseApi.init(DATA_PATH, lang);
baseApi.setImage(ReadFile.readBitmap(bm));
String whiteList = "0123456789";
baseApi.setVariable(TessBaseAPI.VAR_CHAR_WHITELIST, whiteList);
String recognizedText = baseApi.getUTF8Text();
baseApi.end();
第二个:(来自:AndroidImageCrop)
String url="http://jimbocho.ocrgrid.org/cgi-bin/weocr/submit_tesseract.cgi";
response="";
HttpClient client = new DefaultHttpClient();
client.getParams().setParameter(CoreProtocolPNames.PROTOCOL_VERSION, HttpVersion.HTTP_1_1);
HttpPost post=new HttpPost(url);
MultipartEntity entity = new MultipartEntity( HttpMultipartMode.BROWSER_COMPATIBLE );
//test start
try {
Bitmap bm = BitmapFactory.decodeFile("/sdcard/DCIM/test.jpg");
ByteArrayOutputStream bos = new ByteArrayOutputStream();
bm.compress(CompressFormat.JPEG, 75, bos);
byte[] data = bos.toByteArray();
ByteArrayBody bab = new ByteArrayBody(data, "testbin.jpg");
//test end
entity.addPart("userfile", bab);
// For usual String parameters
entity.addPart("outputencoding", new StringBody("utf-8"));
entity.addPart("outputformat", new StringBody("txt"));
post.setEntity( entity );
HttpResponse response = client.execute(post);
BufferedReader reader = new BufferedReader(new InputStreamReader(response.getEntity().getContent(), "UTF-8"));
String sResponse;
StringBuilder s = new StringBuilder();
while ((sResponse = reader.readLine()) != null) {
s = s.append(sResponse);
}
this.response=new String(s.toString());
怎么能帮到我? 感谢。