我需要将一行文件中的多行作为一个逗号分隔的参数传递给脚本。每当我尝试将处理文件的输出用作单个字符串时,逗号就会变成分隔符。我怎么能这样做?
测试用例:
[user@host]$ #Here is a word list, my target words are on lines starting with "1,"
[user@host]$ cat word_list_numbered.txt
1,lakin
2,chesterfield
3,sparkplug
4,unscrawling
5,sukkah
1,girding
2,gripeful
3,historied
4,hypoglossal
5,nonmathematician
1,instructorship
2,loller
3,containerized
4,duodecimally
5,oligocythemia
1,nonsegregation
2,expecter
3,enterrologist
4,tromometry
5,salvia
[user@host]$ #Here is a mock operation, it just outputs the number of args, I want all selected words as one argument
[user@host]$ cat operation.sh
echo "This script has $# arguments"
[user@host]$ #Here is a script that outputs the needed words as comma delimited
[user@host]$ grep '^1,' word_list_numbered.txt | tr -d '1,' | tr '\n' ',' | sed 's/,$//' lakin,girding,instructorship,nonsegregation[user@host]$
[user@host]$ #Here is the operation script receiving that comma delimited list
[user@host]$ ./operation.sh $(grep '^1,' word_list_numbered.txt | tr -d '1,' | tr '\n' ',' | sed 's/,$//')
This script has 4 arguments
[user@host]$ #oops, too many arguments
[user@host]$ ./operation.sh foo,bar
This script has 1 arguments
[user@host]$ ./operation.sh foo bar
This script has 2 arguments
[user@host]$
详细说明:
答案 0 :(得分:2)
awk和xargs的组合怎么样?
awk -F, -v ORS=, '$1==1{print $2}' file | xargs ./operation.sh
或者如果您介意以逗号结尾:
awk -F, -v ORS=, '$1==1{print $2}' file | sed 's/,$//' | xargs ./operation.sh
测试:
$ cat operation.sh
echo "This script has $# arguments"
echo "$@"
$ awk -F, -v ORS=, '$1==1{print $2}' file | sed 's/,$//' | xargs ./operation.sh
This script has 1 arguments
lakin,girding,instructorship,nonsegregation
$ cat file
1,lakin
2,chesterfield
3,sparkplug
4,unscrawling
5,sukkah
1,girding
2,gripeful
3,historied
4,hypoglossal
5,nonmathematician
1,instructorship
2,loller
3,containerized
4,duodecimally
5,oligocythemia
1,nonsegregation
2,expecter
3,enterrologist
4,tromometry
5,salvia
如果没有xargs,那就是:
./operation.sh "$(awk -F, -v ORS=, '$1==1{print $2}' file | sed 's/,$//')"
答案 1 :(得分:1)
awk
的替代方法是在bash中使用命令替换来填充包含文件内容的数组,然后再将所有行连接到一个逗号分隔的字符串中以通过到operation.sh
:
#!/bin/bash
## function simulating operation.sh
operation() { printf "%s\n" "$1"; }
a=( $(<word_list_numbered.txt) )
b="${a[0]}$(printf ",%s" ${a[@]:1} )"
operation $b
exit 0
<强>输出强>
$ bash csvlist.sh
1,lakin,2,chesterfield,3,sparkplug,4,unscrawling, ..<snip>.. 5,salvia
答案 2 :(得分:1)
假设:
$ echo "$tgt"
1,lakin
2,chesterfield
3,sparkplug
4,unscrawling
5,sukkah
1,girding
2,gripeful
3,historied
4,hypoglossal
5,nonmathematician
1,instructorship
2,loller
3,containerized
4,duodecimally
5,oligocythemia
1,nonsegregation
2,expecter
3,enterrologist
4,tromometry
5,salvia
Perl:
$ echo "$tgt" | perl -F',' -lane '$A[++$#A]=$F[1] if $F[0]=="1"; END{ print join(",", @A) }'
lakin,girding,instructorship,nonsegregation
答案 3 :(得分:0)
过滤并通过awk获取单词并使用粘贴加入它们。
$ awk -F ',' '$1==1{print $2}' word_list_numbered.txt | paste -s -d ',' -
lakin,girding,instructorship,nonsegregation
$ ./operation.sh "$(awk -F ',' '$1==1{print $2}' word_list_numbered.txt | paste -s -d ',' - )"
This script has 1 arguments
$
更新:用双引号括起来。