我这里有一个将数字转换为单词的代码但问题是每当我调用将数字转换为单词的函数时, 它只会读取实际数字ex: convert_number_to_words(30) 但是如果我使用一个从数据库中提取数据的变量: convert_number_to_words($ due),它就不会读取该数字。 有谁知道如何解决这个问题?提前谢谢。
这里是将数字转换为单词的函数代码:
function convert_number_to_words($number) {
$hyphen = '-';
$conjunction = ' and ';
$separator = ', ';
$negative = 'negative ';
$decimal = ' point ';
$dictionary = array(
0 => 'zero',
1 => 'one',
2 => 'two',
3 => 'three',
4 => 'four',
5 => 'five',
6 => 'six',
7 => 'seven',
8 => 'eight',
9 => 'nine',
10 => 'ten',
11 => 'eleven',
12 => 'twelve',
13 => 'thirteen',
14 => 'fourteen',
15 => 'fifteen',
16 => 'sixteen',
17 => 'seventeen',
18 => 'eighteen',
19 => 'nineteen',
20 => 'twenty',
30 => 'thirty',
40 => 'fourty',
50 => 'fifty',
60 => 'sixty',
70 => 'seventy',
80 => 'eighty',
90 => 'ninety',
100 => 'hundred',
1000 => 'thousand',
1000000 => 'million',
1000000000 => 'billion',
1000000000000 => 'trillion',
1000000000000000 => 'quadrillion',
1000000000000000000 => 'quintillion'
);
if (!is_numeric($number)) {
return false;
}
if (($number >= 0 && (int) $number < 0) || (int) $number < 0 - PHP_INT_MAX) {
// overflow
trigger_error(
'convert_number_to_words only accepts numbers between -' . PHP_INT_MAX . ' and ' . PHP_INT_MAX,
E_USER_WARNING
);
return false;
}
if ($number < 0) {
return $negative . convert_number_to_words(abs($number));
}
$string = $fraction = null;
if (strpos($number, '.') !== false) {
list($number, $fraction) = explode('.', $number);
}
switch (true) {
case $number < 21:
$string = $dictionary[$number];
break;
case $number < 100:
$tens = ((int) ($number / 10)) * 10;
$units = $number % 10;
$string = $dictionary[$tens];
if ($units) {
$string .= $hyphen . $dictionary[$units];
}
break;
case $number < 1000:
$hundreds = $number / 100;
$remainder = $number % 100;
$string = $dictionary[$hundreds] . ' ' . $dictionary[100];
if ($remainder) {
$string .= $conjunction . convert_number_to_words($remainder);
}
break;
default:
$baseUnit = pow(1000, floor(log($number, 1000)));
$numBaseUnits = (int) ($number / $baseUnit);
$remainder = $number % $baseUnit;
$string = convert_number_to_words($numBaseUnits) . ' ' . $dictionary[$baseUnit];
if ($remainder) {
$string .= $remainder < 100 ? $conjunction : $separator;
$string .= convert_number_to_words($remainder);
}
break;
}
if (null !== $fraction && is_numeric($fraction)) {
$string .= $decimal;
$words = array();
foreach (str_split((string) $fraction) as $number) {
$words[] = $dictionary[$number];
}
$string .= implode(' ', $words);
}
return $string;
}
这里是将打印转换为单词的数字的代码:
echo convert_number_to_words($due);
答案 0 :(得分:0)
首先检查它是字符串还是数字,然后传递给函数。如果它期望一个整数而不是一个整数应该传递给它。
用它来检查
if(is_numeric($due))
{
echo 'is a numeric value';
}
else
{
//conert due to an int
$due=(int)$due;
}
然后将值传递给函数。