Python：subprocess.Popen返回OSError：[Errno 2]没有这样的文件或目录

Question

在我的剧本中，我有以下一行：

proc = subprocess.Popen(["qstat", "-xml", "-u", "*", "-r", "-s", "r"],  stdout=subprocess.PIPE)

当我运行它时工作正常，但当它被设置为cronjob时我会回来：

Traceback (most recent call last): File 
File "/seq/software/current/bin/createOpsDashboard.py", line 171, 
in get_pod_occupied_slots
proc = subprocess.Popen(["qstat", "-xml", "-u", "*", "-r", "-s", "r"], stdout=subprocess.PIPE)
File "/software/free/Linux/redhat_5_x86_64/pkgs/python_2.7.1-sqlite3-rtrees/lib/python2.7/subprocess.py", line 672, in __init__ errread, errwrite)
File "/software/free/Linux/redhat_5_x86_64/pkgs/python_2.7.1-sqlite3-rtrees/lib/python2.7/subprocess.py", line 1202, in _execute_child
raise child_exception
OSError: [Errno 2] No such file or directory

造成这种情况的原因是什么？ cronjob正在调用一个加载Python-2.7的shell脚本，然后调用真实的脚本。

Answer 1

使用＆＃34; qstat＆＃34;的完整路径，例如＆＃34;在/ usr / local / bin中/ qstat命令＆＃34 ;. cronjob的PATH环境变量通常限制为默认路径（例如/ bin：/ usr / bin）。